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frosja888 [35]
3 years ago
9

Reiko started a business selling home medical supplies. She spent $6500 to obtain her merchandise, and it costs her $550 per wee

k for general expenses. She eams $900 per week in sales.
Mathematics
1 answer:
polet [3.4K]3 years ago
5 0

if she spent 6500 at the beginning and it cost 550 per week, 900-550=350 gain per week... 350 times 19 is 6650 so it takes 19 weeks for them to make a gain

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Which graph represents the function f(x) =-lx-2l-1​
zimovet [89]

It’s the second one from the right

Since there’s a - behind x it means it has to be facing down so it’s either 2 or 4

Now it’s x-2 and we know that x moves the opposite so it needs to move 2 to the right so the answer is 2

6 0
3 years ago
The Alvin Secretarial Service procures temporary office personnel for major corporations. They have found that 60% of their invo
Hoochie [10]

Answer:

0.9942 = 99.42% probability that at least 6 of the invoices will be paid within ten working days

Step-by-step explanation:

For each invoice, there are only two possible outcomes. Either they are paid within 10 working days, or they are not. The probability of an invoice being paid within 10 working days is independent of other invoices. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

60% of their invoices are paid within ten working days.

This means that p = 0.6

A random sample of 18 invoices is checked.

This means that n = 18

What is the probability that at least 6 of the invoices will be paid within ten working days?

Either less than 6 are paid within 10 working days, or at least 6 are paid. The sum of the probabilities of these events is 1. So

P(X < 6) + P(X \geq 6) = 1

We want P(X \geq 6). So

P(X \geq 6) = 1 - P(X < 6)

In which

P(X < 6) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5)

Then

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{18,0}.(0.6)^{0}.(0.4)^{18} \approx 0

P(X = 1) = C_{18,1}.(0.6)^{1}.(0.4)^{17} \approx 0

P(X = 2) = C_{18,2}.(0.6)^{2}.(0.4)^{16} \approx 0

P(X = 3) = C_{18,3}.(0.6)^{3}.(0.4)^{15} = 0.0002

P(X = 4) = C_{18,4}.(0.6)^{4}.(0.4)^{14} = 0.0011

P(X = 5) = C_{18,5}.(0.6)^{5}.(0.4)^{13} = 0.0045

P(X < 6) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) = 0 + 0 + 0 + 0.0002 + 0.0011 + 0.0045 = 0.0058

Finally

P(X \geq 6) = 1 - P(X < 6) = 1 - 0.0058 = 0.9942

0.9942 = 99.42% probability that at least 6 of the invoices will be paid within ten working days

6 0
3 years ago
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Furkat [3]

Answer:

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Step-by-step explanation:

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Makovka662 [10]
MMK so saying that a=3 and b=4 means substitute the letters, with the numbers. I'm not gonna do it for you but ill help you out a bit. 
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11.   3^2 + 1=
14.   (3)(4)/3=

I think you can do the rest on ur own my friend. Hope this helped :)   
6 0
3 years ago
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Write an algorithm to find sum of first ten even numbers?
Agata [3.3K]

Answer:

n(n+1)

This is the answer I know

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3 years ago
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