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alina1380 [7]
4 years ago
10

Please answer correctly !!!!!! Will mark brainliest !!!!!!!!!!!

Mathematics
1 answer:
Sholpan [36]4 years ago
7 0
X•X= x^2, 4•2=8, 8x^2
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Ricardos bill at a restaurant is $57.32. He wants to leave an 18% tip. what will the new total be including tip.​
Margarita [4]

Answer:

$67.64

Step-by-step explanation:

57.32*1.18=67.6376\\

Rounding it off to the nearest cent, we get $67.64.

8 0
3 years ago
Find the perimeter of a regular polygon with an interior angle of 90° and side length 3.5 ft.
PSYCHO15rus [73]

Answer:

p=14 ft

Step-by-step explanation:

The figure that meets these conditions is the square

The perimeter:

4(3.5) = 14 ft.

Hope this helps

6 0
2 years ago
HELP PLEASE I’LL MARK YOU BRAINLIEST IF YOU GET IT RIGHT
Darina [25.2K]
Well I know this is not linear becuase then the y-values would be going up by a constant number. So, B and C are gone. Personally, A looks a bid odd. So, If I were you I'd go with D.

Just my opinion, not 100%
4 0
3 years ago
I don't need the answer I NEED someone to explain this to me, I'm really struggling with this, and can someone walk me through t
Whitepunk [10]
<h2>Answer:</h2>

I hope it will helps u

<h2>Step-by-step explanation:</h2>

As given

x²-3x-10

Now according to the one of the rule of factorization ,

we have to find such two values whose product becomes equal to the

"product of first and last term " and if we sum those numbers it should be equal to the "middle term of it".

so such numbers are   -5x and +2x

if we add or multiply them we get the above

as  adding    -5x+2x=-3x  (middle term)

also multiplying   -5x*2x=-10x²  (product of 1st and last term)

so now , we can write as,

x²-3x-10

=x²-5x+2x-10

now making groups of 2 terms,

=(x²-5x)+(2x-10)

now common

=x(x-5)+2(x-5)

now common(x-5)

=(x-5)(x+2)   This is the required factors.....

6 0
3 years ago
How to find the slope
nirvana33 [79]

Answer:

m= \frac{y_2-y_1}{x_2-x_1}

Step-by-step explanation:

use this formula if you're having two points or a graph

6 0
3 years ago
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