Answer:
a) C(x) = 15000/x + 6x +80
b) Domain of C(x) { R x>0 }
Step-by-step explanation:
We have:
Enclosed area = 1500 ft² = x*y from which y = 1500 / x (a) where x is perpendicular to the river
Cost = cost of sides of fenced area perpendicular to the river + cost of side parallel to river + cost of 4 post then
Cost = 10*y + 2*3*x + 4*20 and accoding to (a) y = 1500/x
Then
C(x) = 10* ( 1500/x ) + 6*x + 80
C(x) = 15000/x + 6x +80
Domain of C(x) { R x>0 }
Answer:
60,000
Step-by-step explanation:
Let the total people in the household be 100%
If 80 percent of the households have cable television, 60 percent of the households have videocassette recorders and the number of households that have both cable television and videocassette recorders is 'x' percent. The number of households having ONLY cable television will be 80-x while households having ONLY videocassette will be 60-x.
To get x, we will have;
80-x + 60-x + x = 100
140-x = 100
x = 140-100
x = 40
This shows that 40% of the households have both cable television and videocassette.
If there are 150,000 households in the city, then the number of households that have both cable television and videocassette recorders could be 40% of 150,000
= 40/100 × 150,000
= 60,000
Number of households that owns both television and videocassette could be from 60,000.