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3 years ago

13

Harrison rode his bike 6/10 Of a mile to the park shade the model then write 6/10 as a decimal to show how far Harrison rode his

bike

1 answer:

alexira [117]3 years ago

4 0

6/10 as a decimal would be 0.6

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Suppose that Y takes on the values {0, 1, 2, 3}, each with probability 1/4. Take a random sample of 5 numbers from this distribu

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Answer:

The total number of samples that give this outcome is 5.

Step-by-step explanation:

Since Y takes values in {0,1,2,3}, For us to have that $Y_1+Y_2+Y_3+Y_4+Y_5=1$ implies that all of them are zero but one. The one that is non-zero necessarily is equal to 1. To calculate the number of samples that give this outcome is equivalent to counting the total number of ways in which we can pick the i-index such that $Y_i=1$ . Note that in this case we can either choose Y1 to be 1, Y2 to be 1 and so on. So, the total number of samples that give this outcome is 5.

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3 years ago

3. What is the area of the triangle below? Round your

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Answer is A because when you work it out the area is 110.500 and rounding it makes it -

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3 years ago

How can we use the graph of a logarithmic function to verify the domain of a function?PLEASE HELP

guajiro [1.7K]

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3 years ago

What do 15/140 equal

Virty [35]

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3 years ago

Read 2 more answers

A real estate agent has 8 master keys to open several new homes. Only 1 master key will open any given house. If 40% of these ho

riadik2000 [5.3K]

Answer:

Step-by-step explanation:

Suppose F represents the value that a room is unlocked.

Then, we can assume that the probability of unlocked homes is:

P(unlocked homes) = P(U)

P(unlocked homes) = 40%

P(unlocked homes) = 0.40

Also, let us represent the value of the locked room with G.

P(locked homes) = P(G)

P(locked homes) = (1 - 0.40)

P(locked homes) = 0.60

Let the probability of selecting a correct key be P(S)

It implies that for the agent to use 3 keys, we have a combination of $^8C_3$ possible ways for the set of keys.

Now; since only one will open the house, then:

P(select correct key) = P(S)

$P(S) = \dfrac{ (^1_1) (^7_2) }{ ^8_3 }$

$P(S) = \dfrac{21}{56}$

P(S) = 0.375

Finally, for the real estate agent to have access to specific homes supposing the agent select three master keys at random prior to the time he left his office, Then:

P(F ∪ (G∩S) = P(F) + P(G∩S)

P(F ∪ (G∩S) = P(F) + P(G) × P(S)

P(F ∪ (G∩S) = 0.40 + (0.60×0.375)

P(F ∪ (G∩S) = 0.40 + 0.225

P(F ∪ (G∩S) =0.625

5 0

2 years ago