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Sunny_sXe [5.5K]
3 years ago
6

At the animal shelter, there are 4 dogs for every 3 cats. Only dogs and cats are accepted (let in) at the shelter. If there are

24 dogs currently at the shelter, how many animals are at the shelter?
Mathematics
1 answer:
artcher [175]3 years ago
7 0

Answer:

There are 42 animals at the shelter

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1/2+2+8+32+...+1024 find the sum of the series
adell [148]

Answer:

I need to know what ... means.

Step-by-step explanation:


5 0
3 years ago
After 8 points are added to each score in a sample, the mean is found to be M= 40. What was the value for the original mean
MArishka [77]

Answer:

The value for the original mean = 32

Step-by-step explanation:

Here, we want to calculate the original value of the mean.

Let the number of samples be n

Mathematically;

mean = Total value/n

Now, we added 8 to each of values; total value added = 8 * n = 8n

Now, for the new mean of 40; we have

(Total value + 8n)/n = 40

Total value + 8n = 40n

Total value = 40n -8n

Total value = 32n

kindly recall from the beginning of the solution;

mean = Total value/n

mean = 32n/n

mean = 32

So the original value of the mean is 32

6 0
3 years ago
I have 98 apples I give my one of my friends 50 how much apples do I have left​
Thepotemich [5.8K]
The answer is 48. 98 - 50 = 48 apples left :)
7 0
2 years ago
Read 2 more answers
Task Directions: Ms. Chang's class decides to order posters that advertise a walkathon to raise money for
mamaluj [8]

Answer:

a.

Clear Prints = 2p

Sue = 15 + 0.5p

b.  10 posters

c.  See Below

d.  Clear Prints

e. See Below

Step-by-step explanation:

<u>Complete Question:</u>

<em>Ms. Chang’s class decides to order posters that advertise a walkathon to raise money for a local charity. Ichiro obtains quotes from two different companies.Clear Prints charges $2 per poster. Posters by Sue charges $15 plus $.50 per poster.</em>

<em>a. For each company, write an equation Ichiro could use to calculate the cost for any number of posters.</em>

<em>b. For what number of posters is the cost the same for both companies? Explain.</em>

<em>c. Which company do you think the class should buy posters from? Explain your reasoning.</em>

<em>d. If Ms. Chang’s class has an $18 budget for posters, which company do you think the class should buy posters from? </em>

<em>e. If Ms. Chang donates an additional $10 for ordering posters, does it impact the decision made? What factors influenced your decision?</em>

<em />

<u>Solution:</u>

a.

Let the number of posters be "p" so

Clear Print would take 2 * p or "2p"

Sue would take a fixed cost of $15 and 0.5p, so "15 + 0.5p"

b.

We want cost of both to be same. So we can equate:

2p=15 + 0.5p

Now, using algebra, we can solve for "p", the number at which both of the printers will cost same. Lets do this:

2p=15 + 0.5p\\2p-0.5p=15\\1.5p=15\\p=10

So, for 10 posters, the cost of both will be same

c.

It depends.

If the number of posters they order is LESS THAN 10, they should order from Clear Prints. If the number of posters they print is "10", then they can choose any one of the printers since cost would be same. If they print more than 10 posters, then they should choose to go with Sue, as it will cost less.

d.

If the budget is $18, they can get:

Clear Prints = 18/2 = 9 posters made

Sue = 15 already gone as fixed cost, so remaining is 18 - 15 = 3

At 0.5 per poster, 3/0.5 = 6 posters

So, taking Clear Prints would be better.

e.

The budget of 18 is increase by 10, so the budget is:

18 + 10 = $28

From clear prints, you can get:

28/2 = 14 posters

From Sue, you can get:

28 - 15(fixed cost) = 13 left for posters

13/0.5 = 26 posters

Definitely, Sue gives more, so decision made at $18 budget to get Clear Prints would be impacted because they should now go with Sue since it will give them better deal and more posters.

5 0
3 years ago
Factor the polynomial function over the complex numbers. f(x)=x4+9x3+15x2+9x+14 Enter your answer in the box. f(x)=
Nostrana [21]

Answer:

(x+2)(x+7)(x+i)(x-i)

Step-by-step explanation:

I just took the quiz.

5 0
3 years ago
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