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3 years ago

10

Let ∠D be an acute angle such that cosD=0.64. Use a calculator to approximate the measure of ∠D to the nearest tenth of a degree

.

2 answers:

Aleks04 [339]3 years ago

7 0

Answer:

50.2 degreees

Step-by-step explanation:

I did math

sertanlavr [38]3 years ago

4 0

Answer:

50.2°

Step-by-step explanation:

$\cos \angle D = 0.64\\\\\angle D = \cos^{-1}(0.64)\\\\\angle D = 50.20818\\\\\angle D \approx 50.2\degree$

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OLEGan [10]

Part A: The algebraic equation for the situation is 2x - 3 = 5

Part B: Bob has 4 brand new music CD's

Step-by-step explanation:

Translate the situation into an algebraic equation:

Ann has 5 brand new music CD’s, which is 3 less than twice the amount that Bob (x) has
Find the value of x (the number of brand new CD's Bob has)

Part A:

∵ Bob has x brand new CD's

∵ Ann has 5 brand new music CD’s, which is 3 less than twice

the amount that Bob has

- That means multiply x by 2 and then subtract 3 from the product

and equate the answer by 5

∵ Twice x 2x

∵ 3 less than twice x = 2x - 3

∴ 2x - 3 = 5

The algebraic equation for the situation is 2x - 3 = 5

Part B:

Let us solve the equation to find the value of x

∵ 2x - 3 = 5

- Add 3 to both sides

∴ 2x = 8

- Divide both sides by 2

∴ x = 4

Bob has 4 brand new music CD's

Learn more:

You can learn more about the algebraic expressions in brainly.com/question/1600376

#LearnwithBrainly

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4 years ago

PLEASE HELP ASAP ILL GIVE 40 POINTS TO ANYONE THAT WILL ANSWER CORRECTLY JUST LOOK AT SCREENSHOT BELOW

AnnyKZ [126]

129. Just did the math

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3 years ago

Read 2 more answers

How long would it take for a ball dropped from the top of a 576576-foot building to hit the ground? Round your answer to two dec

Scorpion4ik [409]

Answer:

5.98 s

Step-by-step explanation:

576 ft = 576 / 3.28 = 175.56 m

Let g = 9.81 m/s2. The time it takes for the ball to fall from 165.56 m high to the ground is

$s = gt^2/2$

$t^2 = 2s/g = 2*175.56/9.81 = 35.8$

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4 years ago

Select the correct answer.

Galina-37 [17]

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I just took this quiz and got it correct.

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3 years ago

Stephen kicked a ball inside. The equation that represents the height h in feet of the ball after being kicked and elapsed amoun

kodGreya [7K]

Answer:

The maximum height of the ball is: 14.0625ft

Step-by-step explanation:

The missing information is:

$h(t) = 30t - 16t^2$

Required

The maximum height the ball attained

First, we calculate the time to reach the maximum height.

For a function: $h(t) = at^2 + bt + c$

The maximum is: $t = \frac{-b}{2a}$

So, the maximum of $h(t) = 30t - 16t^2$ is:

$t = \frac{-b}{2a}$

Where

$a = -16; b = 30$

So:

$t = -\frac{30}{2*-16}$

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$t = \frac{30}{32}$

$t = 0.9375$

The maximum height is then calculated as:

$h(t) = 30t - 16t^2$

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$h(0.9375) = 28.125- 14.0625$

$h(0.9375) = 14.0625$

8 0

3 years ago