What is 4 1/5+3 1/10 a. 7 2/15 b. 7 3/10 c. 7 1/5 d. 7 1/50
1 answer:
You might be interested in
The face value of the largest 20-year term policy which Maria can buy without spending more than $300 annually is $158,000.
<h3>What is face value?</h3>Face is the term used in finance, is used for the amount which has to be paid to the policyholder at the time of maturity.
Maria, age 28, wants to pay no more than $300 a year in life insurance.
The period for this policy is 20-year term.
Annual life insurance premium (per 1,000 dollars of face value) for age 28.
- A 10-year term for female is 1.28,
- A 15 year term for female is 1.54,
- A 20 year term for female is 1.89,
- A whole life for female is 9.46.
For the 20 year term for female is 1.89 and annular premium is $300. Thus, the face value is,
Thus, the face value of the largest 20-year term policy which Maria can buy without spending more than $300 annually is $158,000.
Learn more about the face value here;
The confidence interval is 
.
We first find the mean. Add together all of the data points and divide by 6, the number of data points; the mean is 77.28.
Next we find the standard deviation. Find the difference between each data point and the mean; square it; find the sum; divide by the number of data points; take the square root. The standard deviation is 3.32.
To find the margin of error, we calculate the z-score associated with this level of confidence. 100-90 = 10% = 0.1; 0.1/2 = 0.05; 1-0.05 = 0.95. Using a z-table (http://www.z-table.com) we see that this is between two scores, 1.64 and 1.65; we will use 1.645.
The margin of error is given by
z * (σ/√n) = 1.645*(3.32/√6) = 2.23.
Thus the confidence interval is 77.28 +/ 2.23.
We first find the mean. Add together all of the data points and divide by 6, the number of data points; the mean is 77.28.
Next we find the standard deviation. Find the difference between each data point and the mean; square it; find the sum; divide by the number of data points; take the square root. The standard deviation is 3.32.
To find the margin of error, we calculate the z-score associated with this level of confidence. 100-90 = 10% = 0.1; 0.1/2 = 0.05; 1-0.05 = 0.95. Using a z-table (http://www.z-table.com) we see that this is between two scores, 1.64 and 1.65; we will use 1.645.
The margin of error is given by
z * (σ/√n) = 1.645*(3.32/√6) = 2.23.
Thus the confidence interval is 77.28 +/ 2.23.