Answer:
D'G' = 52.5 units
Step-by-step explanation:
Since the dilatation is centred at the origin then multiply the original coordinates by the scale factor 3.5
D' = (1 × 3.5, 7 × 3.5 ) = (3.5, 24.5 )
G' = (- 8 × 3.5, - 5 × 3.5 ) = (- 28, - 17.5 )
Calculate D'G' using the distance formula
d = ![\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2 }](https://tex.z-dn.net/?f=%5Csqrt%7B%28x_%7B2%7D-x_%7B1%7D%29%5E2%2B%28y_%7B2%7D-y_%7B1%7D%29%5E2%20%20%20%20%7D)
with (x₁, y₁ ) = D' (3.5, 24.5) and (x₂, y₂ ) = G' (- 28, - 17.5)
D'G' = ![\sqrt{(-28-3.5)^2+(-17.5-24.5)^2}](https://tex.z-dn.net/?f=%5Csqrt%7B%28-28-3.5%29%5E2%2B%28-17.5-24.5%29%5E2%7D)
= ![\sqrt{(-31.5)^2+42^2}](https://tex.z-dn.net/?f=%5Csqrt%7B%28-31.5%29%5E2%2B42%5E2%7D)
= ![\sqrt{992.25+1764}](https://tex.z-dn.net/?f=%5Csqrt%7B992.25%2B1764%7D)
= ![\sqrt{2756.25}](https://tex.z-dn.net/?f=%5Csqrt%7B2756.25%7D)
= 52.5 units
vertex = (3,- 5 )
given a quadratic in standard form : y = ax² + bx + c ( a ≠ 0 ), then
the x-coordinate of the vertex is
= - ![\frac{b}{2a}](https://tex.z-dn.net/?f=%5Cfrac%7Bb%7D%7B2a%7D)
y = x² - 6x + 4 is in standard form
with a = 1, b = - 6 and c = 4, hence
= -
= 3
substitute this value into the equation for y- coordinate
y = 3² - 6(3) + 4 = 9 - 18 + 4 = - 5
vertex = (3, - 5 ) → second table
Answer:
z=re ^iθ =2e ^i 3/π
Step-by-step explanation:
hope this helps
Answer:
One thing that must be true is that the objects will cause some leaning because their masses are unequal, judging from the volume that the objects can hold. One thing that could be true is that the triangle could be heavier than the square, leading to a leaning toward the left. The second pic cannot be true, for there are too much mass concentrated on one side to maintain equilibrium.