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3 years ago

NEED ASAP I WILL GIVE BRAINLEYEST What is the value of the expression 22 + 82 ÷ 22? 8 10 17 20

Mathematics

1 answer:

natita [175]3 years ago

3 0

Answer:

Exact Form:

283 /11

Decimal Form:

25. 72

Mixed Number Form:

25 8 /11

Step-by-step explanation:

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kaleb had 63 dollars. if he spent 7 dollars on new books, what is the ratio of money he still has to money he's spent?

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He would have 56 dollars left

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Write each sum as a product of two factors for 6•7+3•7

lapo4ka [179]

65 is the product of this

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Suppose that one person in 10,000 people has a rare genetic disease. There is an excellent test for the disease; 98.8% of the pe

nirvana33 [79]

Answer:

A)The probability that someone who tests positive has the disease is 0.9995

B)The probability that someone who tests negative does not have the disease is 0.99999

Step-by-step explanation:

Let D be the event that a person has a disease

Let $D^c$ be the event that a person don't have a disease

Let A be the event that a person is tested positive for that disease.

P(D|A) = Probability that someone has a disease given that he tests positive.

We are given that There is an excellent test for the disease; 98.8% of the people with the disease test positive

So, P(A|D)=probability that a person is tested positive given he has a disease = 0.988

We are also given that one person in 10,000 people has a rare genetic disease.

So, $P(D)=\frac{1}{10000}$

Only 0.4% of the people who don't have it test positive.

$P(A|D^c)$ = probability that a person is tested positive given he don't have a disease = 0.004

$P(D^c)=1-\frac{1}{10000}$

Formula: $P(D|A)=\frac{P(A|D)P(D)}{P(A|D)P(D^c)+P(A|D^c)P(D^c)}$

$P(D|A)=\frac{0.988 \times \frac{1}{10000}}{0.988 \times (1-\frac{1}{10000}))+0.004 \times (1-\frac{1}{10000})}$

P(D|A)= $\frac{2470}{2471}$ =0.9995

P(D|A)= $0.9995$

A)The probability that someone who tests positive has the disease is 0.9995

(B)

$P(D^c|A^c)$ =probability that someone does not have disease given that he tests negative

$P(A^c|D^c)$ =probability that a person tests negative given that he does not have disease =1-0.004

=0.996

$P(A^c|D)$ =probability that a person tests negative given that he has a disease =1-0.988=0.012

Formula: $P(D^c|A^c)=\frac{P(A^c|D^c)P(D^c)}{P(A^c|D^c)P(D^c)+P(A^c|D)P(D)}$

$P(D^c|A^c)=\frac{0.996 \times (1-\frac{1}{10000})}{0.996 \times (1-\frac{1}{10000})+0.012 \times \frac{1}{1000}}$

$P(D^c|A^c)=0.99999$

B)The probability that someone who tests negative does not have the disease is 0.99999

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3 years ago

A store sells tea cups in sets of 9 and saucers in sets of 12. The store sold the same number of individual cups and saucers in

BlackZzzverrR [31]

The first five multiples of 9 are 9 18 27 36 45 I hope that's what you mean.

The prime factors of 9 and 12 are

9: 3 * 3

12: 3 * 2 * 2

The LCM is 3*3*2*2 is 36

The store sold 4 sets of cups ans 3 sets saucers. Answer

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barxatty [35]

Answer:

I think it's 4y

Step-by-step explanation:

I think it's 4y is because if y = 0 they all work but 4y which is 0 while all the others are 4

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