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Art [367]
3 years ago
10

How do you find the diameter for 10​

Mathematics
2 answers:
Ostrovityanka [42]3 years ago
7 0

Answer:

fxigxitxiyxiyxigxitxitxoyc9ycitxoy

Step-by-step explanation:

xoyxitxitx9yc9yxigx9yx9yxogxigx8tx8t

tatuchka [14]3 years ago
4 0

Answer:

Step-by-step explanation:

If the circumference of the circle is 10 cm, then the diameter is 10 cm/π, or 3.18 cm. If you know the area of the circle, divide the result by π and find its square root to get the radius; then multiply by 2 to get the diameter.

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Let X1,X2......X7 denote a random sample from a population having mean μ and variance σ. Consider the following estimators of μ:
Viefleur [7K]

Answer:

a) In order to check if an estimator is unbiased we need to check this condition:

E(\theta) = \mu

And we can find the expected value of each estimator like this:

E(\theta_1 ) = \frac{1}{7} E(X_1 +X_2 +... +X_7) = \frac{1}{7} [E(X_1) +E(X_2) +....+E(X_7)]= \frac{1}{7} 7\mu= \mu

So then we conclude that \theta_1 is unbiased.

For the second estimator we have this:

E(\theta_2) = \frac{1}{2} [2E(X_1) -E(X_3) +E(X_5)]=\frac{1}{2} [2\mu -\mu +\mu] = \frac{1}{2} [2\mu]= \mu

And then we conclude that \theta_2 is unbiaed too.

b) For this case first we need to find the variance of each estimator:

Var(\theta_1) = \frac{1}{49} (Var(X_1) +...+Var(X_7))= \frac{1}{49} (7\sigma^2) = \frac{\sigma^2}{7}

And for the second estimator we have this:

Var(\theta_2) = \frac{1}{4} (4\sigma^2 -\sigma^2 +\sigma^2)= \frac{1}{4} (4\sigma^2)= \sigma^2

And the relative efficiency is given by:

RE= \frac{Var(\theta_1)}{Var(\theta_2)}=\frac{\frac{\sigma^2}{7}}{\sigma^2}= \frac{1}{7}

Step-by-step explanation:

For this case we assume that we have a random sample given by: X_1, X_2,....,X_7 and each X_i \sim N (\mu, \sigma)

Part a

In order to check if an estimator is unbiased we need to check this condition:

E(\theta) = \mu

And we can find the expected value of each estimator like this:

E(\theta_1 ) = \frac{1}{7} E(X_1 +X_2 +... +X_7) = \frac{1}{7} [E(X_1) +E(X_2) +....+E(X_7)]= \frac{1}{7} 7\mu= \mu

So then we conclude that \theta_1 is unbiased.

For the second estimator we have this:

E(\theta_2) = \frac{1}{2} [2E(X_1) -E(X_3) +E(X_5)]=\frac{1}{2} [2\mu -\mu +\mu] = \frac{1}{2} [2\mu]= \mu

And then we conclude that \theta_2 is unbiaed too.

Part b

For this case first we need to find the variance of each estimator:

Var(\theta_1) = \frac{1}{49} (Var(X_1) +...+Var(X_7))= \frac{1}{49} (7\sigma^2) = \frac{\sigma^2}{7}

And for the second estimator we have this:

Var(\theta_2) = \frac{1}{4} (4\sigma^2 -\sigma^2 +\sigma^2)= \frac{1}{4} (4\sigma^2)= \sigma^2

And the relative efficiency is given by:

RE= \frac{Var(\theta_1)}{Var(\theta_2)}=\frac{\frac{\sigma^2}{7}}{\sigma^2}= \frac{1}{7}

5 0
4 years ago
What is the quotient of 5/6 divided 2/12
Alex17521 [72]

Answer: 60/12 or 5

Step-by-step explanation: Find the reciprical of 2/12. That is 12/2. Then, multiply 5/6 and 12/2. 12x5 is 60 and 6x2 is 12.

5 0
3 years ago
WILL GIVE BRAINLIST i cant remember how this one goes at all​
SOVA2 [1]

Answer:

B' = (-2,2)

Step-by-step explanation:

So to solve this you need to find the current coordinates of B.

B = (-5,4)

So it says the translation is (x+3, y-2)

Let us substitute in the values

(-5 + 3, 4 - 2)

So the new coordinate is

(-2,2)

3 0
4 years ago
Read 2 more answers
What is the base area ??
mamaluj [8]
the answer to your question for a base area is 100
6 0
3 years ago
Which expression is not equivalent to 54x−12 from the amswers below?
DochEvi [55]

The equation that is not equal to 54x-12 is (12x-3)4

(12x-3)4 equals 48x-12 while the other ones equal 54x-12

6 0
2 years ago
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