In the diagram below is a regular pentagon ABCDE, side EB is drawn.
1 answer:
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Option C
The distance of a spin of one full rotation is 31.4 feet
<em><u>Solution:</u></em>
Given that,
A circular merry-go-round has a radius of 5 feet
Radius = 5 feet
We have to find the distance of spin for one full rotation
Distance covered in 1 full of rotation is equal to circumference of circle
<em><u>The circumference of circle is given as:</u></em>
Where "r" is the radius
Thus the distance of a spin of one full rotation is 31.4 feet