SIDE LENGTH OF TRIANGLE: 2.14 inches
SIDE LENGTH OF HEXAGON: 6 inches
To solve this problem, we know that the shapes have equal sides as it states “equilateral triangle”. A triangle has 3 sides and a hexagon has 6 sides. We are told the perimeters are the same so you can set their perimeters equal to each other to solve for x. You would get this : 3(1.4x + 2) = 6(0.5x +2)
With basic algebra you would get x= 5
Then you substitute that value into the length sides of the triangle and hexagon. For the triangle you would approx get 2.14 inches and for the hexagon 6 inches
Y=8.50x+5.00
56=y
-56=8.50x+5.00
56=8.50x+5.00
-5.00 -5.00
51=8.50x
÷8.5 ÷8.5
6=x <u>HE CAN BUY 6 DVDS</u>
Answer:
7π
Step-by-step explanation:
SO first find the area of the whole circle
which has a radius of 3
a=πr^2
So 3^2=9
9π
Now the two circles which are the same in area due to having the same radius
so if you plug in the 1 for radius the answer would just be π or 1π
now multiply that by 2 becuase there are 2 identical circles
π*2=2π
Now subtract
9π-2π=7π
2/1
Step-by-step explanation:
_1/3y=_1
y=_1+3/1
y=2/1