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2 years ago

What is the equation of the line that passes through (1, 2) and is parallel to the line whose equation is 2x+y-1=0?

Mathematics

1 answer:

tresset_1 [31]2 years ago

3 0

Answer:

The equation of the line that passes through (1, 2) is y = - 2x + 4

Step-by-step explanation:

2x + y - 1 = 0

2x + y - 1 + 1 = 0 + 1

2x + y = 1

2x - 2x + y = 1

y = - 2x + 1

parallel lines have the same slope, so the equation line will be -2

plug in the point, y = mx + b (x, y)

y = (-2)x + b , (1, 2)

(2) = (-2)(1) + b

2 = -2 + b

2 + 2 = -2 + 2 + b

4 = b

y = - 2x + 4

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