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3 years ago

7(2 + 6 – 4d) = pl help me I don’t get it

Mathematics

1 answer:

____ [38]3 years ago

6 0

Answer and Step-by-step explanation:

To solve, we need to first add 2 + 6 together, then distribute the 7.

7(2 + 6 - 4d)

7(8 - 4d)

56 - 28d <- This is the answer.

#teamtrees #PAW (Plant And Water)

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Solve the two step equations

disa [49]

Hello!

1) -3x - 4 = 23

-3x = 23 + 4

-3x = 27

x = 27 : (-3)

x = -9

2) x/2 - 12 = -4

x - 24 = -8

x = -8 + 24

x = 16

3) 6a + (-1) = 10

6a - 1 = 10

6a = 10 + 1

6a = 11

a = 11 : 6

a = 11/6

4) -(x + 2) = 12

x + 2 = -12

x = -12 - 2

x = -14

5) 7a + 12 = 10

7a = 10 - 12

7a = -2

a = -2 : 7

a = -2/7

6) -4(a + 2) = 12

a + 2 = -3

a = -3 - 2

a = -5

Good luck! :)

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3 years ago

Which ordered pair is a solution of the inequality?

valentinak56 [21]

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3 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

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Consider the function below. (If an answer does not exist, enter DNE.) g(x) = 190 + 8x3 + x4 (a) Find the interval of increase.

galben [10]

Answer:

The interval of increase of g(x) is $(-6,+\infty)$ .

Step-by-step explanation:

The interval of increase occurs when first derivative of given function brings positive values. Let be $g(x) = 190 + 8 \cdot x^{3} + x^{4}$ , the first derivative of the function is:

$g'(x) = 24 \cdot x ^{2} + 4\cdot x^{3}$

$g'(x) = 4 \cdot x^{2}\cdot (6+x)$

The following condition must be met to define the interval of increase:

$4\cdot x^{2} \cdot (x+6) > 0$

The first term is always position due to the quadratic form, the second one is a first order polynomial and it is known that positive value is a product of two positive or negative values. Then, the second form must satisfy this:

$x + 6 > 0$

The solution to this inequation is:

$x > - 6$

Now, the solution to this expression in interval notation is: $(-6,+\infty)$

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3 years ago