Answer:
if he drove 9 hours it would 378 miles
We would need to look over the z table to find the area under the standard normal distribution curve to the left of z = 1.04. Then we'll subtract it from 1 to get the proportion of a normal distribution corresponding to z scores greater than 1.04.
By looking at the z table, we can see that the area to the left of z = 1.04 is 0.8508. So the proportion of a normal distribution to the right of z = 1.04 is 1 – 0.8508 = 0.1492.
The answer is 0.1492.
Answer:
5 chickens
Step-by-step explanation:
Let's set chickens and pigs with variables "c" and "p" respectively.
We know there a 16 animals in all, so there are:
c+p=16
We know there are 54 legs and chickens have 2 legs and pigs have 4 legs each:
2c+4p=54
Now we have our system of equations:
c+p=16
2c+4p=54
We are trying to find the number of chickens, so we write the first equation in respect to c.
p=16-c
Substituting the first derived equation to equation two:
2c+64-4c=54
Simplifying:
64-2c=54
2c=10
c=5
So there are 5 chickens.
We have given the table of number of male and female contestants who did and did not win prize
The probability that a randomly selected contestant won prize given that contestant was female is
P(contestant won prize / Contestant was female)
Here we will use conditional probability formula
P(A/B) = 
Let Event A = selected contestant won prize and
event B = selected contestant is famale
Then numerator entity will
P(A and B) = P(Contestant won prize and Contestant is female)
= Number of female contestant who won prize / Total number of contestant
= 3 /(4+9+3+10)
= 3 / 26
P(A and B) = 0.1153
P(B) = P(contestant is female )
= Number of female contestant / Total number of contestants
= (3+10) / 26
P(B) = 0.5
Now P(A / B) = 
= 0.1153 / 0.5
P(A / B) = 0.2306
The probability that randomly selected contestant won prize given that contestant is female is 0.2306
Converting probability into percentage 23.06%
The percentage that randomly selected contestant won prize given that contestant is female is 23%