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yKpoI14uk [10]
3 years ago
13

Find the area of the isosceles triangle below

Mathematics
1 answer:
garri49 [273]3 years ago
3 0

Answer:

37

Step-by-step explanation:

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Which set of side lengths create a right triangle ?
I am Lyosha [343]

Answer:

(8, 15 and 17)

Step-by-step explanation:

\sqrt{10^{2} +28^{2} } \neq 29

\sqrt{6^{2} +8^{2} } \neq 13

\sqrt{7^{2} +12^{2} } \neq 14

\sqrt{8^{2} +15^{2} } =17

3 0
3 years ago
(2a-4a2+8)+(5a2 -5a+6)
lana [24]
A^2-3a+14 is the answer :)
8 0
2 years ago
Read 2 more answers
A spinner used in a board game is divided into 12 equally sized sectors. Seven of these sectors indicate that the player should
forsale [732]

Answer:

9.3 inches

Step-by-step explanation:

The computation of the radius of the spinner be given below:

Let us assume the same be x

So

We know that

Total area of the sector = one-sixth of the total area of the spinner

Given that

45.1 =  1 ÷ 6 × π × r^2

r^2 = 45.1 × 6 ÷ π

r^2 = 86.1

r = 9.279

= 9.3 inches

3 0
3 years ago
Help please it’s needed
julia-pushkina [17]

Answer:

The reasonings I provided are just examples (they are true, though!). Hope this helps!

3 0
3 years ago
Write the vector u as a sum of two orthogonal vectors, one of which is the vector projection of u onto v, projvu u=(-8,8) , v= (
Jobisdone [24]

Answer:

none of the given options is true

Step-by-step explanation:

Given: u=(-8,8) , v= (-1,2)

To find: vectors w_1,w_2 such that u=w_1+w_2

Solution:

A vector is a quantity that has both magnitude and direction.

proj_vu=\frac{u\cdot v}{\left | v \right |^2}(v)\\=\frac{(-8,8)\cdot (-1,2)}{(\sqrt{ (-1)^2+2^2})^2}(-1,2)\\=\frac{8+16}{5}(-1,2)\\=\frac{1}{5}(-24,48)\\=(-4.8,9.6)

Let w_1=(-4.8,9.6)

So,

w_2=u-w_1\\=(-8,8)-(-4.8,9.6)\\=(-8+4.8,8-9.6)\\=(-3.2,-1.6)

So, u = (-4.8,9.6)+(-3.2,-1.6)

So, none of the given options is true

8 0
3 years ago
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