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Whitepunk [10]
3 years ago
10

5 tenths + 8 hundreths

Mathematics
1 answer:
gayaneshka [121]3 years ago
3 0

Answer:

50,800

Step-by-step explanation:

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So if you need 30 bags but you can buy 200 bags for 6.19 how much does it cost for 1 bag?​
maw [93]

Answer:

0.03095

Step-by-step explanation:

         0.03095

200   6.19000

        -600

           1900

          -1800

             1000

            -1000

             0

4 0
2 years ago
Joey decides to empty his piggy bank and count his money. His bank is filled with only nickels and dimes. Joey counted a total o
xxTIMURxx [149]

Answer:

Joey has 18 nickles and 27 dimes in his piggy bank.

Step-by-step explanation:

1 nickle = 5 cents

1 dime = 10 cents

$1 = 100 cents

$3.15 = 135 cents

Let

n represent the number of nickles, n>=0

d represent the number of dimes, d>=0

Joey counted a total of 45 coins that added up to $3.15:

n + d = 45

5n + 10d = 315

n = 18 nickles

d = 27 dimes

5 0
3 years ago
Ben claims that 12 is a factor of 24. how can you check whether he is correct
AlekseyPX
Take 12 from 24 and if the the answer is 12 then it's a factor.
7 0
3 years ago
If ad=30 and dc=30 what is the length of bd
DerKrebs [107]

BD =√30 +√30

BD = 2√30

Here you go

7 0
2 years ago
* Let S = Span {(2,-1, 1), (3, 1, 1), (1, 2, 0)}. (i) Calculate the dimension of S.
Sholpan [36]

The span of 3 vectors can have dimension at most 3, so 9 is certainly not correct.

Check whether the 3 vectors are linearly independent. If they are not, then there is some choice of scalars c_1,c_2,c_3 (not all zero) such that

c_1 (2,-1,1) + c_2 (3,1,1) + c_3 (1,2,0) = (0,0,0)

which leads to the system of linear equations,

\begin{cases} 2c_1 + 3c_2 + c_3 = 0 \\ -c_1 + c_2 + 2c_3 = 0 \\ c_1 + c_2 = 0 \end{cases}

From the third equation, we have c_1=-c_2, and substituting this into the second equation gives

-c_1 + c_2 + 2c_3 = 2c_2 + 2c_3 = 0 \implies c_2 + c_3 = 0 \implies c_2 = -c_3

and in turn, c_1=c_3. Substituting these into the first equation gives

2c_1 + 3c_2 + c_3 = 2c_3 - 3c_3 + c_3 = 0 \implies 0=0

which tells us that any value of c_3 will work. If c_3 = t, then c_1=t and c_2 = -t. Therefore the 3 vectors are not linearly independent, so their span cannot have dimension 3.

Repeating the calculations above while taking only 2 of the given vectors at a time, we see that they are pairwise linearly independent, so the span of each pair has dimension 2. This means the span of all 3 vectors taken at once must be 2.

3 0
2 years ago
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