Step-by-step explanation:
-cz+6z-tz=83
z(-c+6-t)=83
z(-c+6-t)/(-c+6-t)=83/(-c+6-t)
z=83/(-c+6-t)
Answer:
x=-5, y=2. (-5, 2).
Step-by-step explanation:
2x+y=-8
3x-5y=-25
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5(2x+y)=5(-8)
3x-5y=-25
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10x+5y=-40
3x-5y=-25
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13x=-65
x=-65/13
x=-5
2(-5)+y=-8
-10+y=-8
y=-8-(-10)=-8+10=2
Answer:
0.1274
Step-by-step explanation:
Let X be the random variable that measures the number of children who get their own coat.
Then, the expected value of X is
E[X] = 1P(X=1) + 2P(X=2)+3P(X=3)+...+10P(X=10)
The probability that a child gets her or his coat is
P(X=1) = 1/10
To compute the probability that 2 children get their own coat, we notice that there are 10! possible permutations of coats. The two children can get their coat in only one way, the other 8 coats can be arranged in 8! different positions, so the probability that 2 children get their own coat is
P(X=2) = 8!/10! = 1/(10*9) and
2P(X=2) = 2/(10*9)
Similarly, we can see that the probability that 3 children get their own coat is
P(X=3) = 7!/10! = 1/(10*9*8) and
3P(X=3) = 3/(10*9*8*7)
and the expected value of X would be
E[X] = 1/10 + 2/(10*9) + 3/(10*9*8)+...+10/10! = 0.1274
Answer:
nah I'll pass, I just need the points :)
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