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3 years ago

What’s the answer to 6x + 3y =

Mathematics

2 answers:

yaroslaw [1]3 years ago

5 0

The correct answer is 12

Alex73 [517]3 years ago

4 0

Answer:

The last answer; 12.

Step-by-step explanation:

In order to solve this, use substitution. Since it gives you an equation for y, substitute that equation in the other formula as y. This will give you:

$6x+3(-2x+4)=?$

Then simplify:

$6x-6x+12=?$

Since 6x - 6x cancels out, you are left with 12.

$?=12\\$

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4.05 LC)

Goshia [24]

Answer:

Step-by-step explanation:

we know this because it is the only part of the graph that is moving downwards, meaning its decreasing. P is an example of increasing, Q is 'neutral' and s is also increasing.

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3 years ago

How do you find slope

alisha [4.7K]

Step-by-step explanation:

Hi there!

To find slope you use the change of y over change of x formula. You first need to ordered pairs to plug into the equation.

Formula:

(Y1-Y2)/(X1-X2)

7 0

3 years ago

Read 2 more answers

Between x = 2 and x = 3, which function has a greater average rate of change than y = 1 3 -x ?

Fudgin [204]

Y = 1 3 -x = left[y \right] = \left[ 3-x\right][y]=[3−x]

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3 years ago

Steve climbed up Mt. McKinney to an elevation of 5000 feet above sea level. His brother, Sam, dove 150 feet below the sea level

Allushta [10]

Answer:

They would be 5,150 feet apart.

Step-by-step explanation:

5,000 + 150 = 5,150

7 0

4 years ago

What is the following product? <br>(4x square root 5x^2 + 2^2 square root 6)^2

tangare [24]

The product is $104 x^{4}+16 \sqrt{30} x^{4}$

Explanation:

The given expression is $\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}$

We need to determine the product of the given expression.

First, we shall simplify the given expression.

Thus, we have,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x \sqrt{5} x+2 x^{2} \sqrt{6}\right)^2$

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x^{2} \sqrt{5}+2 x^{2} \sqrt{6}\right)^2$

Expanding the expression, we have,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x^{2} \sqrt{5}+2 x^{2} \sqrt{6}\right)\left(4 x^{2} \sqrt{5}+2 x^{2} \sqrt{6}\right)$

Now, we shall apply FOIL, we get,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x^{2} \sqrt{5}\right)^{2}+2 ( 2 x^{2} \sqrt{6})(4 x^{2} \sqrt{5})+\left(2 x^{2} \sqrt{6}\right)^{2}$

Simplifying the terms, we have,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=16 \cdot 5 x^{4}+16 \sqrt{30} x^{4}+4 \cdot 6 x^{4}$

Multiplying, we get,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=80 x^{4}+16 \sqrt{30} x^{4}+24 x^{4}$

Adding the like terms, we get,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=104 x^{4}+16 \sqrt{30} x^{4}$

Thus, the product of the given expression is $104 x^{4}+16 \sqrt{30} x^{4}$

7 0

3 years ago