*see attachment for the figure referred to
Answer/Step-by-step explanation:
1. PN = 29
MN = 13
PM = ?
(Segment addition postulate)
(subtract MN from each side)
(substitute)
2. PN = 34, MN = 19, PM = ?
(sediment addition postulate)
(subtract MN from each side)
(substitute)
3. PM = 19, MN = 23, PN = ?
(Segment addition postulate)
(substitute)
4. MN = 82, PN = 105, PM = ?
(segment addition postulate)
(subtract MN from each side)
(substitute)
5. PM = 100, MN = 100, PN = ?
(Segment addition postulate)
(substitute)
Answer: -3
Since the both equal the same value we can combine the into -8x-2=-6x+4.
From there you can solve from whatever side you want, and the answer is -3.
2k - 4 = 2 + k
(Subtract both sides by k)
k - 4 = 2
(Add both sides by 4)
k = 6
A. First move all to the left side of the equation(Normal form)
x^3 - 49x= 0
B. Factor out an x, which is the GCF (Factored form)
x(x^2 - 49) = 0
C. Find solutions by making each x piece equal to 0. The first part is just x=0 and the second part is just factoring the difference of squares and then solving.
x=0, x^2 - 49 =0
x=0, x + 7 = 0, x - 7 = 0
Therefore, the answers for Part C are:
x = 0, x = -7, x = 7
Answer:
<em><u>The answer is 4 </u></em><em><u> </u></em><em><u>because </u></em><em><u>the</u></em><em><u> </u></em><em><u>2</u></em><em><u> </u></em><em><u>over</u></em><em><u> </u></em><em><u>3</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>canceled</u></em><em><u> </u></em><em><u>out</u></em><em><u /></em>
