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3 years ago

(3xy)^2x^4y/x^5 A. 3y^3 B. 3xy^3 C. 9xy^3 D. 9x^5y^3

Mathematics

2 answers:

a_sh-v [17]3 years ago

7 0

3 x 3 = 9 so it’s c add the snap susy2755

VMariaS [17]3 years ago

6 0

Answer:

It is the third one

Step-by-step explanation

3 times 3 equals 9.

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Q(a+1) - 2q(a) if q(x) = x²+3x+4

siniylev [52]

$q(x) = {x}^{2} + 3x + 4$

_________________________________

Step(1)

To find q(a) we just need to put a instead of x in q(x) function.

Let's do it...

$q(a) = {a}^{2} + 3a + 4$

Multiply sides by -2 :

$- 2q(a) = - 2( {a}^{2} + 3a + 4)$

$- 2q(a) = - 2 {a}^{2} - 6a - 8$

_________________________________

Step (2)

To find q(a+1) we just need to put a+1 instead of x in q(x) function.

Let's do it...

$q(a + 1) = ({a + 1})^{2} + 3(a + 1) + 4 \\$

$q(a + 1) = {a}^{2} + 2a + 1 + 3a + 3 + 4 \\$

$q(a + 1) = {a}^{2} + 5a + 8$

_________________________________

Step (3)

$q(a + 1) - 2q(a) =$

${a}^{2} + 5a + 8 - 2 {a}^{2} - 6a - 8 = \\$

$- {a}^{2} - a = - a(a + 1)$

And we're done.

Thanks for watching buddy good luck.

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8 0

4 years ago

A car dealership is comparing the sales of two employees. The equation that represents Kevin’s sales is S = 60n-5, where n repre

BARSIC [14]

Answer:

I been trying to look for that answer for so long but can we help each other at least

6 0

3 years ago

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During which one-day interval did she work the most hours?

Karo-lina-s [1.5K]

Um well lets see there is no question so the day that ends in y

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4 years ago

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18. Brown eyes (B) are dominant to blue eyes (b). The presence of freckles (F) is dominant to the absence of freckles (f). What

MrRissso [65]

Answer:

For bbff we have only 6.3% probability

Step-by-step explanation:

If the parents are heterozygous for both traits, them they are represented by:

BbFf × BbFf

Parent 1: BbFf

Parent 2: BbFf

We have to find the percentage of occurence of bb × ff, which is a child that has blue eyes and no freckles, with no dominant factor.

By distributing the possibilities in a Punnett square, <em>vide</em> picture. We have the following possibilities:

Genotype Count Percent

bBfF 4 25

BBfF 2 12.5

bBFF 2 12.5

bBff 2 12.5

bbfF 2 12.5

BBFF 1 6.3

BBff 1 6.3

bbFF 1 6.3

bbff 1 6.3

For bbff we have only 6.3% probability

6 0

3 years ago

Montraie has a coin collection. He keeps 10 of the coins in his box, which is 20% of the collection. How many total coins are in

jek_recluse [69]

By definition of percentages, we conclude that Montraie has 10 coins saved in his box that come from a collection with a total of 50 coins.

<h3>How to calculate the quantity of coins in a collection</h3>

In this question we know the quantity of coins in a box and such coins are part of the <em>coin</em> collection. By definition of percentage we have the <em>total</em> quantity of coins in the collection:

x = 10*(100/20)

x = 50

By definition of percentages, we conclude that Montraie has 10 coins saved in his box that come from a collection with a total of 50 coins.

To learn more on percentages: brainly.com/question/13450942

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2 years ago