Answer:
The velocities after 739 s of firing of each engine would be 6642.81 m/s in the x direction and 5306.02 in the y direction
Step-by-step explanation:
- For a constant acceleration:
, where 
is the final velocity in a direction after the acceleration is applied, 
is the initial velocity in that direction before the acceleration is applied, a is the acceleration applied in such direction, and t is the amount of time during where that acceleration was applied. - <em>Then for the x direction</em> it is known that the initial velocity is
5320 m/s, the acceleration (the applied by the engine) in x direction is 
1.79 m/s2 and, the time during the acceleration was applied (the time during the engines were fired) of the is 739 s. Then: 
- In the same fashion, <em>for the y direction</em>, the initial velocity is
0 m/s, the acceleration in y direction is 
7.18 m/s2, and the time is the same that in the x direction, 739 s, then for the final velocity in the y direction: 
7.211; Starting from the left to right, x1=3 x2=7, y1=2 y2=8. Plug these in to the distance formula 
(7-3)^2+(8-2)^2
(4)^2+(6)^2
16+36
sqrt 52
7.211
GHE i think because it’s the same degrees
Answer: e. each component be identified by a coding scheme that specifies size, shape, and the type of processing.
Step-by-step explanation:
Group technology is a technique in manufacturing that involves bringing together parts with similar process of manufacturing or function into the same location so that they can all go through the same process. This follows a general saying that problems with similar groups could possibly be solved using a single or similar solution, which could help save time, resources and efforts.
