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rjkz [21]
3 years ago
10

Please help!!! Find the surface area of the prism below. Do not put units in your answer.

Mathematics
1 answer:
ch4aika [34]3 years ago
4 0

Answer:

256.51

Step-by-step explanation:

Find the hypotonuese of the trangle (8^2+ 5^2= c^2) then multiply all of them together then multiply by a 1/2.

Have a good day :)

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Answer: 320,340,360,380,400,420,440

6 0
3 years ago
Help please?
Alla [95]
\bf \begin{array}{clclll}
3^{1001}&\qquad &4^{1002}\\
\uparrow &&\uparrow \\
a&&b
\end{array}\\\\
-----------------------------\\\\
(a+b)^2-(a-b)^2\implies (a^2+2ab+b^2)-(a^2-2ab+b^2)
\\\\\\
a^2+2ab+b^2-a^2+2ab-b^2\implies 2ab+2ab\implies 4ab
\\\\\\
now\qquad 4(3^{1001})(4^{1002})=k12^{1001}\qquad 
\begin{cases}
12^{1001}\\
(4\cdot 3)^{1001}\\
4^{1001}\cdot 3^{1001}
\end{cases}

\bf \\\\\\
4(3^{1001})(4^{1002})=k(4^{1001}\cdot 3^{1001})\implies \cfrac{4(3^{1001})(4^{1002})}{4^{1001}\cdot 3^{1001}}=k
\\\\\\
4\cdot \cfrac{3^{1001}}{3^{1001}}\cdot \cfrac{4^{1002}}{4^{1001}}=k\implies 4\cdot 4^{1002}4^{-1001}=k\impliedby 
\begin{array}{llll}
\textit{same base}\\
\textit{add the}\\
exponents
\end{array}
\\\\\\
4\cdot 4^{1002-1001}=k\implies 4\cdot 4^1=k\implies 16=k
6 0
3 years ago
What is <br> (7x-3) = (12x+12)
Aleks04 [339]

Answer:

x=-3

Step-by-step explanation:

8 0
2 years ago
Find the inverse of
nignag [31]
I hope this helps you

3 0
3 years ago
Simplify by factoring. Assume that all expressions under radicals represent nonnegative numbers.
Nimfa-mama [501]
<h2>Answer:</h2>

<u>x>0 and working with real numbers</u>

10x^2\sqrt{2}

OR

<u>x<0 and working with imaginary/complex numbers</u>

10\sqrt{2}\sqrt{x^4}

OR

<u>Leave it like the following for both systems(Real/Complex) numbers</u>

10\sqrt{2}\sqrt{x^4}

<h2>Step-by-step explanation:</h2>

\sqrt{200x^4}

<u>First simplify</u> \sqrt{200}

\sqrt{200}

<u>Find a perfect square and a non perfect square, which when you multiply the two squares it gives you</u> \sqrt{200}

\sqrt{100} * \sqrt{2} = \sqrt{200}

\sqrt{100} \ \sqrt{2}}

10 \sqrt{2}

<u>Now get the square root of</u> \sqrt{x^4} <u>if we are working with real numbers and  x > 0</u>

\sqrt{x^4} = x^2

<u>If x not > 0 then just leave as</u> \sqrt{x^4}

<u>Now combine it all</u>

10x^2\sqrt{2}

OR

10\sqrt{2}\sqrt{x^4}

5 0
3 years ago
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