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3 years ago

What is 7 + 7 +7+7+7+7 x 0 XD

Mathematics

2 answers:

Pachacha [2.7K]3 years ago

5 0

Uuuummm I think it’s a carrot?

Klio2033 [76]3 years ago

3 0

Answer:

Just simplify the expression and you'll get:

You might be wondering why isn't the answer 0, since anything multiplied by 0 is 0.

It's because to answer this question, you will need to use PEMDAS.

P, Parenthesis.

E, Exponents.

M, Multiply.

D, Divide.

A, Addition.

S, Subtraction.

Since we don't have parenthesis, exponents, a division sign, or subtraction sign.

All we need to do is Mutiply, and Add.

First we multiply, because of the PEMDAS order.

7 * 0 = 0

Then, since we used one of the 7's to multiply. (The one next to the 0)

We add the rest of them, not including the last seven.

There are six, sevens.

But we already used one.

So we will add only the other five.

7 + 7 + 7 + 7 + 7 = 35.

7 * 5 = 35

And that's it.

You got your answer, 35.

You might be interested in

Solve for u -16=8+4u simplify your answer as much as possible

satela [25.4K]

Answer:

U = -6

Step-by-step explanation:

-16 = 8 + 4u

-24 = 4u

-24/4 = 4u/4

-6 = u

6 0

3 years ago

Which is the equation of a hyperbola with directrices at x = ±2 and foci at (5, 0) and (−5, 0)? y squared over 40 minus x square

N76 [4]

The equation of the hyperbola with directrices at x = ±2 and foci at (5, 0) and (−5, 0) is $\frac{x^2}{10} + \frac{y^2}{15} = 1$

<h3>How to determine the equation of the hyperbola?</h3>

The given parameters are:

Directrices at x = ±2
Foci at (5, 0) and (−5, 0)

The foci of a hyperbola are represented as:

Foci = (k ± c, h)

The center is:

Center = (h,k)

And the directrix is:

Directrix, x = h ± a²/c

By comparison, we have:

k ± c = ±5

h = 0

h ± a²/c = ±2

Substitute h = 0 in h ± a²/c = ±2

0 ± a²/c = ±2

This gives

a²/c = 2

Multiply both sides by c

a² = 2c

k ± c = ±5 means that:

k ± c = 0 ± 5

By comparison, we have:

k = 0 and c = 5

Substitute c = 5 in a² = 2c

a² = 2 * 5

a² = 10

Next, we calculate b using:

b² = c² - a²

This gives

b² = 5² - 10

Evaluate

b² = 15

The hyperbola is represented as:

$\frac{(x - k)^2}{a^2} + \frac{(y - h)^2}{b^2} = 1$

So, we have:

$\frac{(x - 0)^2}{10} + \frac{(y - 0)^2}{15} = 1$

Evaluate

$\frac{x^2}{10} + \frac{y^2}{15} = 1$

Hence, the equation of the hyperbola is $\frac{x^2}{10} + \frac{y^2}{15} = 1$

Read more about hyperbola at:

brainly.com/question/3405939

#SPJ1

6 0

2 years ago

Please explain to me how to find y. I’m so confused.

koban [17]

Every triangle angles add up to 180.

So because one angle is 90 degrees you would subtract it from 180 to get 90 and then divide it by two which is 45 degrees.

Hope this helps, have a nice day! :)

7 0

3 years ago

You help in the local cafeteria by emptying the trash barrels. You are paid $4 for each day you work. Let d be the number of day

Andreyy89

4d = $$$$

You would times 4 by the number of days

8 0

3 years ago

Read 2 more answers

What are the ordered pairs of the

9966 [12]

Start by writing the system down, I will use $y$ to represent $f(x)$

$y=x^2-5x+3\wedge y=-3$

Substitute the fact that $y=-3$ into the first equation to get,

$-3=x^2-5x+3$

Simplify into a quadratic form ( $ax^2+bx+c=0$ ),

$x^2-5x+6=0$

Now you can use Vieta's rule which states that any quadratic equation can be written in the following form,

$x^2+x(m+n)+mn=0$

which then must factor into

$(x+m)(x+n)=0$

And the solutions will be $m,n$ .

Clearly for small coefficients like ours $5,6$ , this is very easy to figure out. To get 5 and 6 we simply say that $m=3, n=2$ .

This fits the definition as $5=3+2$ and $6=2\cdot3$ .

So as mentioned, solutions will equal to $m=3, n=2$ but these are just x-values in the solution pairs of a form $(x,y)$ .

To get y-values we must substitute 3 for x in the original equation and then also 2 for x in the original equation. Luckily we already know that substituting either of the two numbers yields a zero.

So the solution pairs are $(2,0)$ and $(3,0)$ .

Hope this helps :)

5 0

3 years ago