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Ber [7]
3 years ago
10

8÷2(2+2) This is 16 not 1

Mathematics
2 answers:
miss Akunina [59]3 years ago
7 0

Step-by-step explanation:

8÷2(2+2) = <u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u>8</u><u>. </u><u> </u><u> </u><u> </u><u> </u>

2(2 + 2)

= <u> </u><u> </u><u> </u><u> </u><u> </u><u>8</u><u>. </u><u> </u><u> </u><u> </u>

4 + 4

= <u> </u><u> </u><u>8</u><u>. </u>

8

= 1

Harrizon [31]3 years ago
6 0

Answer:

using BODMAS

The answer is 1

Step-by-step explanation:

Bracket Order Division Multiplication Addition and Subtraction

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Let angle ladder makes with the ground be x degrees. 

sin x = 11.8/12
x = sin^-1(11.8/12)
x = 79.5 degrees (3 s.f.)

yes it is possible
3 0
3 years ago
PLEASE HELPPPPPPP
uysha [10]

Answer:

the answer would be 1,-8

6 0
2 years ago
Lauren invests money in an account paying simple interest. She invests $50 and no money is added or removed from the investment.
Naily [24]

Answer:

yes

Step-by-step explanation:

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5 0
3 years ago
The gate of a stadium ha two pillars each of height 10ft.with four visible lateral faces and 3ft*3ft bases .the top of eaxh pill
lbvjy [14]

The pillars and the pyramids in the stadium gate means that we have to calculate the area of the items that make up the gate one after the other. At the end of the calculation, the calculated areas are then added up.

The total cost of painting is Rs.21344

First, we calculate the area of 1 side of 1 pillar using:

A = Height * Base

Where

Height = 10ft --- Height of the pillar

Base = 3ft --- Base of the pillar

So:

A = 10ft * 3ft

A = 30ft^2

The area of the 4 sides of the pillar is:

A_2 = 4 * A --- i.e. 4 multiplied by the area of 1 side

A_2 = 4 * 30ft^2

A_2 = 120ft^2

The area of the 2 pillars is:

Area_1 = 2 * A_2 --- i.e. 2 multiplied by the area if 1

Area_1 = 2 * 120ft^2

Area_1 = 240ft^2

Because one part of the pyramid won't be visible, we calculate the area of the pyramid using:

Area = lw + l\sqrt{(w/2)^2 + h^2} + w\sqrt{(l/2)^2 + h^2}

Where:

h = 2 -- the height

l = w = 3 --- the base of the pillar is the length and width of the pyramid.

So, we have:

Area = 3\sqrt{(2/2)^2 + 2^2} + 3\sqrt{(2/2)^2 + 2^2}

Area = 3\sqrt{1 + 4} + 3\sqrt{1 + 4}

Area = 3\sqrt{5} + 3\sqrt{5}

Area = 6\sqrt{5}

For the two pyramids, the area is:

Area_2 = 2 * 6\sqrt 5 -- 2 multiplied by area of 1

Area_2 = 12\sqrt 5

Area_2 = 26.8

So, the total area to be painted is:

Total = Area_1 + Area_2 --- the sum of the area of the pillars and the pyramids

Total = 240+26.8

Total = 266.8ft^2

The unit cost of paint is:

Rate = Rs80 per sq.ft

The total cost of painting is:

Cost = 80 * 266.8

Cost = Rs.21344

Read more at:

brainly.com/question/14320476

7 0
3 years ago
A.Find the perimeter of the triangle.
hammer [34]
A: 5+5+6=11 units
B. You can find the height by dividing the traingle into 2 right traingles with 5 being the hypotenuse and 3 being one of the legs.
5^2=3^2+x^2
25=9+x^2
16=x^2
x=4
Area= 6*4/2= 12 units^2
C. 12*6=$72
5 0
3 years ago
Read 2 more answers
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