All categories

3 years ago

How do you graph x≤−5 on a number line??

Mathematics

2 answers:

Oksi-84 [34.3K]3 years ago

5 0

Answer:

Step-by-step explanation:

x ≤ −5 means that x is less than or equal to -5, which means that -5 is a close circle.

worty [1.4K]3 years ago

3 0

U put the FILLED IN circle on top of the -5 with the arrow going left

You might be interested in

How many three-fourths are in 3?

shutvik [7]

Four three -fourths are in three

7 0

4 years ago

A magazine reports that women trust recommendations from a particular social networking site more than recommendations from any

Misha Larkins [42]

Answer:

a) $p_A$ represent the real population proportion for women

$\hat p_A =\frac{123}{150}=0.82$ represent the estimated proportion for women

$n_A=150$ is the sample size selected for women

b) $p_B$ represent the real population proportion for male

$\hat p_B =\frac{102}{170}=0.6$ represent the estimated proportion for male

$n_B=170$ is the sample size selected for male

c) $(0.82-0.6) - 1.96 \sqrt{\frac{0.82(1-0.82)}{150} +\frac{0.6(1-0.6)}{170}}=0.124$

$(0.82-0.6) + 1.96 \sqrt{\frac{0.82(1-0.82)}{150} +\frac{0.6(1-0.6)}{170}}=0.316$

And the 95% confidence interval would be given (0.124;0.316).

We are confident at 95% that the difference between the two proportions is between $0.124 \leq p_A -p_B \leq 0.316$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Part a

$p_A$ represent the real population proportion for women

$\hat p_A =\frac{123}{150}=0.82$ represent the estimated proportion for women

$n_A=150$ is the sample size selected for women

Part b

$p_B$ represent the real population proportion for male

$\hat p_B =\frac{102}{170}=0.6$ represent the estimated proportion for male

$n_B=170$ is the sample size elected for male

$z$ represent the critical value for the margin of error

Part c

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

The confidence interval for the difference of two proportions would be given by this formula

$(\hat p_A -\hat p_B) \pm z_{\alpha/2} \sqrt{\frac{\hat p_A(1-\hat p_A)}{n_A} +\frac{\hat p_B (1-\hat p_B)}{n_B}}$

For the 95% confidence interval the value of $\alpha=1-0.95=0.05$ and $\alpha/2=0.025$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=1.96$

And replacing into the confidence interval formula we got:

$(0.82-0.6) - 1.96 \sqrt{\frac{0.82(1-0.82)}{150} +\frac{0.6(1-0.6)}{170}}=0.124$

$(0.82-0.6) + 1.96 \sqrt{\frac{0.82(1-0.82)}{150} +\frac{0.6(1-0.6)}{170}}=0.316$

And the 95% confidence interval would be given (0.124;0.316).

We are confident at 95% that the difference between the two proportions is between $0.124 \leq p_A -p_B \leq 0.316$

8 0

3 years ago

What is the maximum height of the projectile? 82 feet 190 feet 226 feet 250 feet.

Contact [7]

The maximum height of the projectile will be 226 feet that is, as per question, the option c.

A quadratic equation , y = ax²+bx+c (equation 1)

given, axis of symmetry is

x = $\frac{b}{2a}$

As per the question:

The path of the projectile is modeled using the equation :

h(t) = -16t²+48t+190 (equation 2)

h(t) = height after t time.

comparing equation 1 and equation 2, we get

a = -16 and b = 48

further, t = $\frac{48}{2(-16)}$

= $\frac{48}{32}$

= 1.5sec

Substituting the found value in equation 2, we get

h(1.5) = -16(1.5)²+48(1.5)+190

h(1.5) = -36+72+190

h(1.5) = 226ft.

Thus, the maximum height of the projectile at 1.5 sec is, 226 feet.

Note that the full question is:

A projectile with an initial velocity of 48 feet per second is launched from a building 190 feet tall. The path of the projectile is modeled using the equation h(t) = –16t2 + 48t + 190.

What is the maximum height of the projectile?

A. 82 feet

B. 190 feet

C. 226 feet

D. 250 feet

To learn more about velocity: brainly.com/question/25749514

#SPJ4

4 0

1 year ago

In the figure below, find the exact value of z.

Naya [18.7K]

9514 1404 393

Answer:

z = 9/2

Step-by-step explanation:

The triangles in the figure are all similar, so the side lengths are proportional.

long side/hypotenuse = z/6 = 6/8

z = 36/8 = 9/2 . . . . multiply by 6

7 0

3 years ago

Need help asap please

Pepsi [2]

Step-by-step explanation:

first of all, your teacher wrote nonsense in the answer options : an area is always given in squared units. never in cubed units (which would be volume).

the area is : 1/2 × perimeter × apothem

the perimeter is simply 12 × 5 = 60 meters.

apothem = (a/2)×cot(pi/12) = 5/2 × cot(pi/12) =

= 9.330127019... meters

so the area is

1/2 × 60 × 9.330127019... = 279.9038106... m²

therefore, the third answer option is correct (although it is m², and not m³).

by the way, you have question 3 wrong. I answered this with the correct apothem calculation in the explanation for question 4.

5 0

2 years ago