All categories

2 years ago

This is a two part question! Please help me!!!

Mathematics

1 answer:

Lana71 [14]2 years ago

4 0

Answer:

A=4ft²

Answerrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrr

Step-by-step explanation:

You might be interested in

A science test, which is worth 100 points, consists of 24 questions. Each question is worth either 3 points or 5 points. If x is

Brilliant_brown [7]

The solution to the system of equations is (x, y) = (10, 14), where x is the number of 3-point questions and y is the number of 5-point questions. The appropriate choice is ...
The test contains 10 three-point questions and 14 five-point questions. (2nd selection)

6 0

3 years ago

George is throwing a party for his son's 9th birthday he orders for sandwiches to the party if each person will eat 2/3 of a san

ddd [48]

Answer:

George can feed 6 people.

Step-by-step explanation:

Given:

Number of sandwiches = 4

Each person eats two-third of a sandwich.

Therefore, number of persons eating 4 sandwich is given as:

$\textrm{Number of persons} =\frac{\textrm{Total sandwiches eaten}}{\textrm{Total sandwiches eaten by 1 person}}$

Therefore,

$\textrm{Number of persons} = \frac{4}{\frac{2}{3}}\\\\\textrm{Number of persons} =4\times \frac{3}{2}=6$

7 0

3 years ago

Most of the savings accounts at stonebrook community bank are earning simple interest. the formula to calculate the amount of si

Maurinko [17]

P=i/rt
,,,,,,,,,,,, ,,,,,,,,,,,,,
Hope it helps

4 0

3 years ago

A confidence interval was used to estimate the proportion of statistics students that are female. A random sample of 72 statisti

jeyben [28]

Answer:

We need a sample of size at least 13.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

90% confidence interval: (0.438, 0.642).

The proportion estimate is the halfway point of these two bounds. So

$\pi = \frac{0.438 + 0.642}{2} = 0.54$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

Using the information above, what size sample would be necessary if we wanted to estimate the true proportion to within ±0.08 using 95% confidence?

We need a sample of size at least n.

n is found when M = 0.08. So

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.08 = 1.96\sqrt{\frac{0.54*0.46}{n}}$