This is a two part question! Please help me!!!
1 answer:
You might be interested in
Answer:
The complete solution is
Step-by-step explanation:
Given differential equation is
3y"- 8y' - 3y =4
The trial solution is
Differentiating with respect to x
Again differentiating with respect to x
Putting the value of y, y' and y'' in left side of the differential equation
The auxiliary equation is
The complementary function is
y''= D², y' = D
The given differential equation is
(3D²-8D-3D)y =4
⇒(3D+1)(D-3)y =4
Since the linear operation is
L(D) ≡ (3D+1)(D-3)
For particular integral
[since
]
[ replace D by 0 , since L(0)≠0]
The complete solution is
y= C.F+P.I