Answer:
a.) Between 0.5 and 3 seconds.
Step-by-step explanation:
So I just went ahead and graphed this quadratic on Desmos so you could have an idea of what this looks like. A negative quadratic, and we're trying to find when the graph's y-values are greater than 26.
If you look at the graph, you can easily see that the quadratic crosses y = 26 at x-values 0.5 and 3. And, you can see that the quadratic's graph is actually above y = 26 between these two values, 0.5 and 3.
Because we know that the quadratic's graph models the projectile's motion, we can conclude that the projectile will also be above 26 feet between 0.5 and 3 seconds.
So, the answer is a.) between 0.5 and 3 seconds.
Answer:
A= -u²n²t²s²arme²
Step-by-step explanation:
Evaluate m, then set it equal to 15.
=15
Evaluate s, the set it equal to 2.
=2
Simplify unitsareminutes.
−u²n²t²s²arme²
List all the solutions.
BN•N=BN²
m=15 ==15
s=2 2==2
answer:X=k/n-3
explain:move all terms to the left side and set equal to zero. then set each factor equ to zero!
I hope this helps
If you would like to write 0.85 in a fractional notation, you can do this using the following steps:
0.85 = 85/100 which simplifies to 17/20 <span>(the common factor of 85 and 100 is 5, so you
can divide both numbers by 5).
The correct result would be 17/20.</span>
Answer:
do yourself a favor and download photomath. It'll save your life
Step-by-step explanation:
