Need help with this question

Solve cos^30- sin^30

11Alexandr11 [23.1K]

Answer:

hi

Step-by-step explanation:

hdisbkaab

bhai kyun dimag kharab kr raha hai chup chap apni mam se puch

4 0

3 years ago

Can someone please solve this problem for me

notsponge [240]

Answer:

D. 28.54

Step-by-step explanation:

To find the area of the shaded region, find the area of the circle and divide it in 4. This will the area of the portion with the triangle.

Now, find the area of the triangle and subtract the two. The resulting value will be the area of the shaded region.

Circle:

$A = \pi r^2\\A = \pi 10^2\\A = 100 \pi\\A = 314$

Divide by 4 for the area of the section with the triangle.

314/4 = 78.5

Triangle:

$A = \frac{1}{2}bh\\A = 0.5 (10 )(10)\\A=0.5(100)\\A=50$

Subtract the two, 78.5 - 50 = 28.5.

7 0

3 years ago

Help pls due today thanks

Elanso [62]

Answer:

18/3 is 6

-18/3 is -6

-18/(-3) is 6

18/(-3) is -6

6 0

3 years ago

In mid-day meal scheme 1/ 10 litre of milk is given to each student of a primary school. If 30 litres of milk are distributed ev

nirvana33 [79]

Answer:

300 students

Step-by-step explanation:

To know the number of students, we must divide the total amount of milk spent by the amount spent for each and in this way we will obtain the value we are looking for, like this (both have the same units of L, so there is no problem ):

30 / (1/10) = 300

that is to say that there are a total of 300 students

5 0

3 years ago

A counselor at a community college claims that the mean GPA for students who have transferred to State University is more than 3

Lena [83]

Answer:

$t=\frac{3.25-3.1}{\frac{0.3}{\sqrt{36}}}=3$

If we compare the p value and the significance level for example $\alpha=1-0.99=0.01$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis.

And the best conclusion would be:

a) Yes. The counselor's claim is valid

Because we reject the null hypothesis in favor to the alternative hypothesis.

Step-by-step explanation:

Data given and notation

$\bar X=3.25$ represent the sample mean

$s=0.3$ represent the sample standard deviation

$n=36$ sample size

$\mu_o =3.1$ represent the value that we want to test

$\alpha$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean is more than 3.1, the system of hypothesis would be:

Null hypothesis: $\mu \leq 3.1$

Alternative hypothesis: $\mu > 3.1$

If we analyze the size for the sample is < 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{3.25-3.1}{\frac{0.3}{\sqrt{36}}}=3$

P-value

The first step is calculate the degrees of freedom, on this case:

$df=n-1=36-1=35$

Since is a one right tailed test the p value would be:

$p_v =P(t_{(35)}>3)=0.00247$

Conclusion

If we compare the p value and the significance level for example $\alpha=1-0.99=0.01$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis.

And the best conclusion would be:

a) Yes. The counselor's claim is valid

Because we reject the null hypothesis in favor to the alternative hypothesis.

5 0

3 years ago