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Brilliant_brown [7]
3 years ago
14

A water jet that leaves a nozzle at 95 m/s at a flow rate of 120 kg/s is to be used to generate power by striking the buckets lo

cated on the perimeter of a wheel. Determine the power generation potential of this water jet. The power generation potential of the water jet is kW.
Engineering
1 answer:
Ksivusya [100]3 years ago
6 0

Answer:

P= 541.5 kW.

Explanation:

Given that

velocity of water after leaving the nozzle ,v= 95 m/s

The mass flow rate of the water , m= 120 kg/s

The power generated P is given as

P=\dfrac{1}{2}mv^2

Now by putting the values in the above equation we get

P=\dfrac{1}{2}\times 120\times 95^2\ W

P=541500  W

The  power in kW will be 541.5 kW.

Therefore the answer will be 541.5 kW

P= 541.5 kW.

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See explaination and attachment for the program code and output

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Kindly check attachment for output.

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