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Elan Coil [88]
2 years ago
8

BRAInly whats the difference between isolation and separation?

Mathematics
1 answer:
Nina [5.8K]2 years ago
8 0

is that separation is the act of separating or the condition of being separated while isolation is (chiefly|uncountable) the state of being isolated, detached, or separated.

also, whats up with the singing?

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PLS PLS PLS PLS HELP ASAP!! WILL MARK BRAINLIEST!
grandymaker [24]

Answer:

1. D

2. y = 15.50x + 450

Step-by-step explanation:

1. Since it is a function, the missing pair can't repeat input values with different output, therefore only option D is unique so is the correct choice.

2. x  > (y - 450)/ 15.50

i) Rita gets paid $450 per week.

ii) She gets $15.50 for every new membership she sells.

iii) let y represent the total pay per week.

iv) let x represent the number of new memberships sold.

v) the equation representing total pay is y = 15.50x + 450.

vii) therefore the equation that represents a higher rate of membership sold is given by  x  > (y - 450)/ 15.50

8 0
2 years ago
Which are like terms in 5x^3 + 3x^2 x + x^3
makvit [3.9K]
The like terms: 5x^3 and x^3
7 0
2 years ago
the length of a rectangle is 4 inches greater than the width. The perimeter of the rectangle is 24 inches what are the dimension
deff fn [24]
Perimeter P=2L+2W
P=24
L=w+4
P=2(w+4)+2w
24=2w+8+2w
24=8+4w
16=4w
w=4
L=8
6 0
3 years ago
wo point charges lie on the $x$ axis. A charge of +6.24 $\mu C$ is at the origin, and a charge of -9.55 $\mu C$ is at $x$ = 12.0
Andreyy89

Answer:

E_n=34,467,075.42\ N/C

Step-by-step explanation:

<u>Electric Field</u>

The electric field produced by a point charge Q at a distance d is given by

\displaystyle E=K\cdot \frac{Q}{d^2}

Where

K = 9\cdot 10^9\ Nw.m^2/c^2

The net electric field is the vector addition of the individual electric fields produced by each charge. The direction is given by the rule: If the charge is positive, the electric field points outward, if negative, it points inward.

Let's calculate the electric fields of each charge at the given point. The first charge q_1=+6.24\mu C=6.24\cdot 10^{-6}C is at the origin. We'll calculate its electric field at the point x=-3.85 cm. The distance between the charge and the point is d=3.85 cm = 0.0385 m, and the electric field points to the left:

\displaystyle E_1=9\cdot 10^9\cdot \frac{6.24\cdot 10^{-6}}{0.0385^2}

E_1=37,888,345.42\ N/C

Similarly, for q_2=-9.55\mu C=-9.55\cdot 10^{-6}C, the distance to the point is 12 cm + 3.85 cm = 15.85 cm = 0.1585 m. The electric field points to the right:

\displaystyle E_2=9\cdot 10^9\cdot \frac{9.55\cdot 10^{-6}}{0.1585^2}

E_2=3,421,270\ N/C

Since E1 and E2 are opposite, the net field is the subtraction of both

E_n=37,888,345.42\ N/C-3,421,270\ N/C

\boxed{E_n=34,467,075.42\ N/C}

6 0
3 years ago
2x2 = 4 4x 10 = 40 x 32 = ?
nikklg [1K]

Answer:

1280

Hope this helped :D

8 0
2 years ago
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