Ask question

Ask question

All categories

3 years ago

8

BRAInly whats the difference between isolation and separation?

1 answer:

Nina [5.8K]3 years ago

8 0

is that separation is the act of separating or the condition of being separated while isolation is (chiefly|uncountable) the state of being isolated, detached, or separated.

also, whats up with the singing?

You might be interested in

How do i use properties of exponents

STatiana [176]

You can use the properties of exponents in three ways: Products of Power and Power to Power

Explanation:

Product of a Power: When you multiply exponentials with the same base, you add their exponents

Power to a Power: When you have a power to a power, you multiply the exponents.
Quotient of Powers: When you divide exponentials with the same base, you subtract the exponents.

3 0

3 years ago

What is the definition for compatible numbers

Svetradugi [14.3K]

Numbers in a problem or related numbers that are easy to work with mentally

4 0

3 years ago

F Andre sold 16 magazine subscriptions this week, would he reach his goal? Explain your reasoning.

Misha Larkins [42]

Answer:

What are some other numbers of magazine subscriptions Andre could have sold and still reached his goal?

Write an inequality expressing that Andre wants to make at least $68.

Write an inequality to describe the number of subscriptions Andre must sell to reach his goal.

8 0

3 years ago

What are the coordinates of each point after quadrilateral ABCD is reflected across the y-axis and then translated 2 units down?

zheka24 [161]

Answer:

$A" =(-1,-1)$ $B" =(-2,1)$

$C" =(-4,1)$ $D" =(-5,-1)$

Step-by-step explanation:

Given

$A = (1,1)$ $B =(2,3)$

$C = (4,3)$ $D = (5,1)$

Required

The new coordinates after reflected across y-axis and shifted 2 units down

When a point is reflected across the y-axis, the rule is:

$(x,y)=>(-x,y)$

So:

$A = (1,1)$ $=> A' = (-1,1)$

$B =(2,3)$ $=> B' = (-2,3)$

$C = (4,3)$ $=> C' = (-4,3)$

$D = (5,1)$ $=> D' = (-5,1)$

When a point is translated 2 units down, the rule is:

$(x,y) => (x,y-2)$

So:

$A = (1,1)$ $=> A' = (-1,1)$ $=> A" =(-1,-1)$

$B =(2,3)$ $=> B' = (-2,3)$ $=> B" =(-2,1)$

$C = (4,3)$ $=> C' = (-4,3)$ $=> C" =(-4,1)$

$D = (5,1)$ $=> D' = (-5,1)$ $=> D" =(-5,-1)$

So, the new coordinates are:

$A" =(-1,-1)$ $B" =(-2,1)$

$C" =(-4,1)$ $D" =(-5,-1)$

5 0

3 years ago

In a triangle ABC, measure of angle B is 90 degrees. AB is 3x-2 units and BC is x+3. If the area of the triangle is 17 sq cm, fo

Scorpion4ik [409]

Answer:

$x=\frac{8}{3}\ cm$

Step-by-step explanation:

we know that

The area of the right triangle ABC is equal to

$A=\frac{1}{2}(AB)(BC)$

we have

$A=17\ cm^2$

$AB=(3x-2)\ cm$

$BC=(x+3)\ cm$

substitute the values

$17=\frac{1}{2}(3x-2)(x+3)$

$34=(3x-2)(x+3)$

$34=3x^2+9x-2x-6$

$3x^2+7x-6-34=0$

$3x^2+7x-40=0$

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$3x^2+7x-40=0$

so

$a=3\\b=7\\c=-40$

substitute in the formula

$x=\frac{-7(+/-)\sqrt{7^{2}-4(3)(-40)}} {2(3)}$

$x=\frac{-7(+/-)\sqrt{529}} {6}$

$x=\frac{-7(+/-)23} {6}$

$x=\frac{-7(+)23} {6}=\frac{16}{6}=\frac{8}{3}$

$x=\frac{-7(-)23} {6}=-5$

therefore

The solution is

$x=\frac{8}{3}\ cm$

6 0

3 years ago