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Snezhnost [94]
2 years ago
8

Vanessa wants to earn an 85% grade in her Statistics class. She has one quiz left to take. On the first 4 quizzes, she received

a 84%, 92%, 83%, 78%. What must she score on the 5th quiz to get the 85% average grade she wants? *
Mathematics
1 answer:
grandymaker [24]2 years ago
6 0

Answer: They would have to score an 88%

Step-by-step explanation:

1.) The mean of 84, 92, 83, and 78 is 337

2.) 337 divided by 4 is 84.25%

3.) If you add 88 to 337 and divide by 5, you get 85%

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A water park charges $5 for entry into the park and an additional $2 for each of the big waterslides. Steven spent $17 on his vi
igomit [66]
5 is a constant - you pay $5 before you go on any of the waterslides.
let the number of waterslides Steven went on = x

5 +2x =17  ($5 plus $2 per waterslide ride = 17)

Answer a is correct.
By the way, Steven went on 6 waterslide rides.
4 0
3 years ago
X divided by six eqauls twentyfive<br><br> x/6=25
mojhsa [17]

Answer:

<h2>x = 150</h2><h2 />

Step-by-step explanation:

x / 6 = 25

x = 25 (6)

x = 150

8 0
3 years ago
Read 2 more answers
I need help this is due Monday
ASHA 777 [7]
1. 259 
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3. 5316
4. 5 
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8 0
2 years ago
Read 2 more answers
The National Transportation Safety Board publishes statistics on the number of automobile crashes that people in various age gro
ra1l [238]

Answer:

a) Null hypothesis:p\leq 0.12  

Alternative hypothesis:p > 0.12  

b) z_{\alpha}=1.64

c) z=\frac{0.134 -0.12}{\sqrt{\frac{0.12(1-0.12)}{1000}}}=1.362  

d) p_v =P(z>1.362)=0.0866  

e) For this case since the statistic is lower than the critical value and the p value higher than the significance level we have enough evidence to FAIL to reject the null hypothesis so then we don't have information to conclude that the true proportion is higher than 0.12

Step-by-step explanation:

Information given

n=1000 represent the random sample selected

X=134 represent the number of young drivers ages 18 – 24 that had an accident

\hat p=\frac{134}{1000}=0.134 estimated proportion of young drivers ages 18 – 24 that had an accident

p_o=0.12 is the value that we want to verify

\alpha=0.05 represent the significance level

Confidence=95% or 0.95

z would represent the statistic

p_v{/tex} represent the p valuePart aWe want to verify if the population proportion of young drivers, ages 18 – 24, having accidents is greater than 12%:  Null hypothesis:[tex]p\leq 0.12  

Alternative hypothesis:p > 0.12  

The statistic would be given by:

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

Part b

For this case since we are conducting a right tailed test we need to find a critical value in the normal standard distribution who accumulates 0.05 of the area in the right and we got:

z_{\alpha}=1.64

Part c

For this case the statistic would be given by:

z=\frac{0.134 -0.12}{\sqrt{\frac{0.12(1-0.12)}{1000}}}=1.362  

Part d

The p value can be calculated with the following probability:

p_v =P(z>1.362)=0.0866  

Part e

For this case since the statistic is lower than the critical value and the p value higher than the significance level we have enough evidence to FAIL to reject the null hypothesis so then we don't have information to conclude that the true proportion is higher than 0.12

8 0
2 years ago
The number of species of coastal dune plants in australia decreases as the latitude, in °s, increases. There are 34 species at 1
Bas_tet [7]

We have been given that the number of species of coastal dune plants in Australia decreases as the latitude, in °s, increases.

Further we know that there are 34 species at 11°s and 26 species at 44°s.

We can express the given information at two ordered pairs as shown below:

(n,l)=(11,34)\text{ and }(n,l)=(44,26)

Let us find slope of the line through these points:

m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}=\frac{26-34}{44-11}=\frac{-8}{33}=-0.2424

Therefore, we can write the equation of line in slope intercept form as:

n=-0.2424l+b

Where b is the y intercept, and we can find its value using one of the two points.

34=-0.2424(11)+b\\34=-2.67+b\\b=34+2.67=36.67

Therefore, the required equation of the linear function is:

n=-0.2424l+36.67

4 0
3 years ago
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