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3 years ago

Ill give brainliest .......

Mathematics

2 answers:

Whitepunk [10]3 years ago

7 0

He gave $100 to the local charity

Step-by-step explanation:

1/5 of 500 is 100

OlgaM077 [116]3 years ago

6 0

Answer:

$100

Step-by-step explanation:

This question asks how much of his money he gave to charity, meaning we must find 1/5 of 500. An easy way to mentally solve this is by dividing 500 into 5 separate, equal parts. This can be done by dividing 500 by 5. If you don't know what 500/5 is you can ignore the 0s for now and just divide 5/5, which is 1. Then, add the 0s back on for an answer of 100. Therefore, because 100 is 1/5 of 500 it must be the answer.

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Answer:

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Step-by-step explanation:

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The domain of f(x) is {-2,0,1}. If f(x) = 4x+1, what is the range?

bekas [8.4K]

The range of function is: {-7,1,5}

Step-by-step explanation:

Given function is:

$f(x) = 4x+1$

Also the domain: {-2,0,1}

In order to find the range,, we have to put the domains values in the function

So,

Putting x = -2

$=4(-2)+1\\= -8+1\\=-7$

Putting x = 0

$=4(0)+1\\= 0+1\\=1$

Putting x = 1

$=4(1)+1\\= 4+1\\= 5$

Hence,

The range of function is: {-7,1,5}

Keywords: domain, range

Learn more about functions at:

#LearnwithBrainly

5 0

3 years ago

Please help!! I only have 30 minutes left!! Given that x and y are positive integers and (x·2)+x(2^2)+(y·2^3)+(y·2^4)=42, what i

Viktor [21]

Answer:

xy = 3

Step-by-step explanation:

The expression to be evaluated is:

$2\cdot x +4\cdot x + 8\cdot y + 16\cdot y = 42$

$6\cdot x + 24\cdot y = 42$

By some algebraic handling:

$6\cdot (x + 4\cdot y) = 42$

Where:

$x+4\cdot y = 7$

There is one possible solution:

x = 3, y = 1

And consequently,

xy = 3

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3 years ago

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Shkiper50 [21]

Answer

The answer and procedures of the exercise are attached in the following archives.

<em>The information complete of the exercise is attached in the sheet.</em>

Step-by-step explanation:

You will find the procedures, formulas or necessary explanations in the archive attached below. If you have any question ask and I will aclare your doubts kindly.

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3 years ago