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madreJ [45]
3 years ago
5

What are the zeros of the polynomial function f(x) = (x + 6)(x + 8)(x + 15)?

Mathematics
1 answer:
Galina-37 [17]3 years ago
4 0
Set all the factors equal to 0 and solve for x.

1) x + 6 = 0

x = -6

2) x + 8 = 0

x = -8

3) x + 15 = 0

x = -15

When the function is graphed, you can see that the function crosses the numbers -15, -8, and -6 on the x-axis. These are the zeros.

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A player chooses one of the numbers 1 through 4. After the choice has been made, two regular four-sided (tetrahedral) dice are r
d1i1m1o1n [39]

Answer:  =\frac{-1}{16}

Step-by-step explanation:

given data:

number to be chosen from = 1,2,3,4.

<u><em>Solution:</em></u>

ways the number can show

2*3*1=6 ways for your number to appear once.

1*1=1 ways for your number to appear twice.

3*3=9 ways for your number not to appear at all

= \frac{6(1) + 1(2) - 9(1)}{16}

= \frac{6+2-9}{16}

=\frac{-1}{16}

expected return of the player is =\frac{-1}{16}

4 0
3 years ago
Simple math
Artist 52 [7]
Paper clip. a paper clip would be about the size of her thumb so she would be able to use. for example, her thumb is 2 paperclips long. therefore the answer would be paperclip.
give me brainliest :D
3 0
3 years ago
Let $a$ and $b$ be nonzero real numbers such that
algol [13]
<h3>Answer:   -7/2</h3>

=========================================================

Explanation:

Let's expand out (2 - 7i)(a + bi) using the FOIL rule

(2 - 7i)(a + bi) = 2a + 2bi - 7ai - 7bi^2

(2 - 7i)(a + bi) = 2a + 2bi - 7ai - 7b(-1)

(2 - 7i)(a + bi) = 2a + 2bi - 7ai + 7b

(2 - 7i)(a + bi) = (2a+7b) + (2bi-7ai)

(2 - 7i)(a + bi) = (2a+7b) + (2b-7a)i

We're told the result is purely imaginary. What this means is that the real part (2a+7b) is zero, while the imaginary part (2b-7a) is nonzero. If both are zero, then we have 0+0i = 0 which is purely real.

For example, the complex numbers 0-7i and 0+2i are purely imaginary.

Let's use the fact that 2a+7b must be zero to do the following steps:

2a+7b = 0

2a = -7b

a = -7b/2

a/b = -7/2 which is the final answer

We must check to see if 2b-7a is nonzero

2b - 7a = 2b - 7(-7b/2)

2b - 7a = 2b + 24.5b

2b - 7a = 26.5b

The result is nonzero if and only if b is nonzero. Luckily we're told b is nonzero at the top of the problem. So we don't have any worries that (2b-7a) is zero.

Therefore, (2a+7b) + (2b-7a)i will be purely imaginary with a/b = -7/2

------------------

A concrete example:

Let a = -14 and b = 4

a/b = -14/4 = -7/2

(2-7i)(a+bi) = (2-7i)(-14+4i) = 0 + 106i which is purely imaginary.

I'll let you do the steps in expanding that out using the FOIL rule.

4 0
1 year ago
For the right triangle shown, the lengths of two sides are given. Find the third side. Leave your answer in simplified, radical
Salsk061 [2.6K]
<span>5^2 + 10^2 = 125
c^2 = 125
c = √125 = √(25•5) = = 5√5</span>

7 0
3 years ago
Read 2 more answers
Find the distance bewtween the points (3,3) and (-1,-2)
Otrada [13]

Answer:

\sqrt{41}

Step-by-step explanation:

\sqrt{(3-(-1))^2+(3-(-2))^2}=\sqrt{16+25}=\sqrt{41}

Hope this helps!

6 0
3 years ago
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