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spin [16.1K]
3 years ago
9

Given that XW bisects AXZ, what theorem or theorems could be used to justify that W is equidistant from two outside rays

Mathematics
1 answer:
maria [59]3 years ago
6 0
Hey! Did you ever figure out the answer? I am stuck on this one as well!
You might be interested in
PLEASE HELP ME I NEED IT<br> X=<br> Y=
vampirchik [111]
X=33 and Y= 57



Step by step explanation if you see the right angle at 57 degrees it part of x so x plus 57 is 90 and 90 minus 57 is 33 so x is 33 and x and y also form a right angle so x plus y should equal 90 and 90 minus 33 is 7 so that’s Y
7 0
3 years ago
Read 2 more answers
28 girls and 38 boys volunteer to plant trees at a school. their teacher wants to put them in groups that have girls AND boys. h
Delvig [45]

Answer:

so 14 can go into 28, 2 times and 19 can go into 38 2 times so the techaer can make 2 group with 14 girls and 19 boys in each group.

Step-by-step explanation:

5 0
3 years ago
Can someone please help and please show work
pychu [463]

Answer:


Step-by-step explanation:

4 and a half

8 0
4 years ago
Check all of the ordered pairs that satisfy the equation below.y=2/5x
zvonat [6]

We are going to do this step by step:

Let's start with option A

A.

X = 25 and Y = 5/2

y=\frac{2}{5}\cdot x=\frac{2}{5}\cdot25=\frac{2\cdot25}{5}=\frac{50}{5}=\frac{5\cdot10}{5\cdot1}=10

In this case, when X = 25 , then Y = 10 ,which is different to 5/2

B.

X = 14 , Y = 35

y=\frac{2}{5}\cdot14=\frac{28}{5}

In case, when X = 14, then Y = 28/5, which is different to 35

C.

X = 40 , Y = 24

y=\frac{2}{5}\cdot40=\frac{80}{5}=16

Similarly, in this case, when X = 40, then Y = 16, which is different to 24

D.

X = 10 , Y=4

y=\frac{2}{5}\cdot10=\frac{20}{5}=4

Now, in this case, we can see that when X = 10, then Y = 4 which is the same as the given value of Y

E.

X = 50 , Y = 20

y=\frac{2}{5}\cdot50=\frac{100}{5}=20

In this case, the values of Y are also the same.

F.

X = 30 , Y = 12

y=\frac{2}{5}\cdot30=\frac{60}{5}=12

Again, in this case, the values of Y are the same, so the pair satisfies the equation.

In conclusion: options D, E and F satisfy the equation

3 0
1 year ago
“Solve the system using elimination” im not good at math so can someone help me
iris [78.8K]

Answer:

No solutions

Step-by-step explanation:

i did this via substitution so i hope it isn't a problem

3x+y=4

6x+2y=−4

Step: Solve 3x+y=4for y:

3x+y+−3x=4+−3x(Add -3x to both sides)

y=−3x+4

Step: Substitute−3x+4foryin6x+2y=−4:

6x+2y=−4

6x+2(−3x+4)=−4

8=−4(Simplify both sides of the equation)

8+−8=−4+−8(Add -8 to both sides)

0=−12

so there are no solutions

hope this helps!!

8 0
3 years ago
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