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3 years ago

(WILL GIVE BRAINLIEST) Lamar plans to paint the net above before folding it into a

Mathematics

1 answer:

Gennadij [26K]3 years ago

8 0

Answer:

B 840cm^2

Step-by-step explanation:

20x10 = 200

20x13 = 260

1/2(10)(12) = 60

200+260+260+60+60= 840

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Simplify (2a+5)6a^2 Can someone help please

Wewaii [24]

Answer:

12a^3+30a^2

Step-by-step explanation:

6a^2(2a+5)

12a^3+30a^2

5 0

3 years ago

Which of the following is the constant ratio of the relation shown in the table?

Dafna11 [192]

There is no constant ratio

4 0

2 years ago

Read 2 more answers

Find the number that makes the ratio equivalent to 7:3. 84:?

vodka [1.7K]

Answer:

Step-by-step explanation:

Divide 84 by 7

84 ÷ 7 = 12

Now multiply 3 by 12

3 × 12 = 36

Then

7 : 3 = 84 : 36

7 0

2 years ago

Read 2 more answers

Which two values of x are roots of the polynomial below? 3x2-3x+1

QveST [7]

Answer:

The roots are

$x=\frac{1}{6} [3+ i\sqrt{3}]$

$x=\frac{1}{6} [3- i\sqrt{3}]$

Step-by-step explanation:

we have

$3x^2-3x+1$

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$3x^2-3x+1=0$

$a=3\\b=-3\\c=1$

substitute in the formula

$x=\frac{-(-3)\pm\sqrt{-3^{2}-4(3)(1)}} {2(3)}$

$x=\frac{3\pm\sqrt{-3}} {6}$

Remember that

$i=\sqrt{-1}$

$x=\frac{1}{6} [3\pm i\sqrt{3}]$

The roots are

$x=\frac{1}{6} [3+ i\sqrt{3}]$

$x=\frac{1}{6} [3- i\sqrt{3}]$

6 0

3 years ago

PLEASE HELP ME!!!!!

MrMuchimi

We know that

if Ray RT bisects QRS
then
the ray RT divide into two equal parts the ∡QRS
so
∡QRT=∡TRS
∡QRT=∡QRS/2-------> 64°/2------> 32°
∡QRT=32°
∡TRS=32°

the answer is
the measures of QRT and TRS is 32°

5 0

3 years ago