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3 years ago

Two lines that lie in the same plane and do not intersect are classified as_____

Mathematics

2 answers:

raketka [301]3 years ago

8 0

The answer is parallel

alexgriva [62]3 years ago

5 0

The answer is parallel.

hope this will help u....

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Find the length and width of a rectangle that has the given area and a minimum perimeter. area: a square centimeters

tresset_1 [31]

There isn't enough information to answer this, what is the given area or perimeter?

4 0

3 years ago

I am trying to figure out how to simplify this problem .

PIT_PIT [208]

Answer:

Step-by-step explanation:11+12/square root of 16

11+(12/4)

11+3

answer is 14

7 0

2 years ago

Read 2 more answers

Is this sequence arithmetic, geometric or neither? 3.5. -4, -7.5...

kvasek [131]

Answer:

Neither

Step-by-step explanation:

If the sequence was geometric, each term would be multiplied by the same multiplier to get to the next one. We can check if the multiplier is the same by taking a term and dividing it by the term before it. For example,

-4/3.5=-1.14285714

-7.5/-4=1.87500

The multiplier between the terms aren't the same so it's not geometric.

For arithmetic, the distances between each term would be the same, and we can take the same idea from the geometric sequence, but use subtraction instead of division

-4-3,5=-7.5

-7.5-(-4)=-3.5

Again, the distances aren't the same, so it's not arithmetic.

8 0

3 years ago

A comet is about 7.63 × 103 miles from Earth. Write this number in standard form.

Simora [160]

Answer:

7630

Step-by-step explanation:

We have that the distance of a comet from Earth is about 7.63*10³ .

This number is given in scientific notation.

We want to write this number in standard form.

Since we are multiplying by a power of 10, we move forward three times.

Therefore in standard form:

$7.63 \times {10}^{3} = 7630$

3 0

3 years ago

NASA launches a rocket at t = 0 seconds. Its height, in meters above sea-level, as a function of time is given by h ( t ) = − 4.

Oliga [24]

Answer:

$\displaystyle 1)48.2 \: \: \text{sec}$

$\rm \displaystyle 2)3021.6 \: m$

Step-by-step explanation:

<h3>Question-1:</h3>

so when flash down occurs the rocket will be in the ground in other words the elevation(height) from ground level will be 0 therefore,

to figure out the time of flash down we can set h(t) to 0 by doing so we obtain:

$\displaystyle - 4.9 {t}^{2} + 229t + 346 = 0$

to solve the equation can consider the quadratic formula given by

$\displaystyle x = \frac{ - b \pm \sqrt{ {b}^{2} - 4 ac} }{2a}$

so let our a,b and c be -4.9,229 and 346 Thus substitute:

$\rm\displaystyle t = \frac{ - (229) \pm \sqrt{ {229}^{2} - 4.( - 4.9)(346)} }{2.( - 4.9)}$

remove parentheses:

$\rm\displaystyle t = \frac{ - 229 \pm \sqrt{ {229}^{2} - 4.( - 4.9)(346)} }{2.( - 4.9)}$

simplify square:

$\rm\displaystyle t = \frac{ - 229 \pm \sqrt{ 52441- 4( - 4.9)(346)} }{2.( - 4.9)}$

simplify multiplication:

$\rm\displaystyle t = \frac{ - 229 \pm \sqrt{ 52441- 6781.6} }{ - 9.8}$

simplify Substraction:

$\rm\displaystyle t = \frac{ - 229 \pm \sqrt{ 45659.4} }{ - 9.8}$

by simplifying we acquire:

$\displaystyle t = 48.2 \: \: \: \text{and} \quad - 1.5$

since time can't be negative

$\displaystyle t = 48.2$

hence,

at 48.2 seconds splashdown occurs

<h3>Question-2:</h3>

to figure out the maximum height we have to figure out the maximum Time first in that case the following formula can be considered

$\displaystyle x _{ \text{max}} = \frac{ - b}{2a}$

let a and b be -4.9 and 229 respectively thus substitute:

$\displaystyle t _{ \text{max}} = \frac{ - 229}{2( - 4.9)}$

simplify which yields:

$\displaystyle t _{ \text{max}} = 23.4$

now plug in the maximum t to the function:

$\rm \displaystyle h(23.4)- 4.9 {(23.4)}^{2} + 229(23.4)+ 346$

simplify:

$\rm \displaystyle h(23.4) = 3021.6$

hence,

about 3021.6 meters high above sea-level the rocket gets at its peak?

5 0

3 years ago