What is 0.64 as a mixed fraction
1 answer:
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Use Law of Cooling:
T0 = initial temperature, TA = ambient or final temperature
First solve for k using given info, T(3) = 42
Substituting k back into cooling equation gives:
At some time "t", it is brought back inside at temperature "x".
We know that temperature goes back up to 71 at 2:10 so the time it is inside is 10-t, where t is time that it had been outside.
The new cooling equation for when its back inside is:
Solve for x:
Sub back into original cooling equation, x = T(t)
Solve for t:
This means the exact time it was brought indoors was about 2.5 seconds before 2:05 PM
T0 = initial temperature, TA = ambient or final temperature
First solve for k using given info, T(3) = 42
Substituting k back into cooling equation gives:
At some time "t", it is brought back inside at temperature "x".
We know that temperature goes back up to 71 at 2:10 so the time it is inside is 10-t, where t is time that it had been outside.
The new cooling equation for when its back inside is:
Solve for x:
Sub back into original cooling equation, x = T(t)
Solve for t:
This means the exact time it was brought indoors was about 2.5 seconds before 2:05 PM
If the roots of the equation f(x)=0 are -4,-1, 2 and 5, then binomials (x+4), (x+1), (x-2) and (x-5) are factors of needed polynomial.
Thus, the polynomial will have form
where a is real coefficient (positive or negative). This polynomial has degree 4 as needed.
The form of the graph depends on the sign of coefficient a. Attached diagrams show two different cases of possible forms of graphs (first one for positive coefficient a, second one for negative coefficient a).
