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3 years ago

X(x-1)-x^2+2x=5 :))))))

Mathematics

2 answers:

Zina [86]3 years ago

4 0

Answer:

$x(x - 1) - {x}^{2} + 2x = 5 \\ {x}^{2} - x - {x}^{2} + 2x = 5 \\ \therefore \: x \: = 5$

AleksAgata [21]3 years ago

4 0

Answer:

x=5

Step-by-step explanation:

$x(x-1)-x^2+2x=5$

expand by using distributive property

$x^2-x-x^2+2x=5$

simplify

x=5

check work by substituting 5 into the original equation and simplify

use PEMDAS

$5(5-1)-5^2+2(5)=5$

$5(4)-25+10=5$

add and subtract (left to right)

20-25+10=5

5=5

The equation is true, thus x=5

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23 - C<6<br> I cannot find the answer can someone help me?

Blababa [14]

Answer:

C > 17

Step-by-step explanation:

23 - C < 6

-23 -23

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-C < -17

multiply both sides by -1

(-c) (-1) > (-17) (-1)

C > 17

5 0

2 years ago

Mr. Gallagher's science class goes bird watching. The picture graph below shows the number of birds the class observes. A) How m

Liono4ka [1.6K]

A)
Monday and Tuesday: 8*6=48
Thursday and Friday: 10*6=60
60-48=12
The answer is 12 more

B)
48+60=108

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4 0

3 years ago

Can someone please help me with a probability question??

yawa3891 [41]

Sure, what's the question?

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3 years ago

F(x)= √x-5. find f-2

rodikova [14]

For this case we have:

Be a function of the form $y = f (x)$

Where:

$f (x) = \sqrt {x-5}$

If we want to find f (-2), we substitute $x = -2$ , then:

$f (-2) = \sqrt {-2-5}\\f (-2) = \sqrt {-7}$

Since we have a negative root, the result will be given by complex numbers. By definition:

$\sqrt {-1} = i$

So:

$f (-2) = \sqrt {7} i$

Answer:

$f (-2) = \sqrt {7} i$

3 0

3 years ago

Without plotting points, let M=(-2,-1), N=(3,1), M'= (0,2), and N'=(5, 4). Without using the distanceformula, show that segments

kramer

Given:

M=(x1, y1)=(-2,-1),

N=(x2, y2)=(3,1),

M'=(x3, y3)= (0,2),

N'=(x4, y4)=(5, 4).

We can prove MN and M'N' have the same length by proving that the points form the vertices of a parallelogram.

For a parallelogram, opposite sides are equal

If we prove that the quadrilateral MNN'M' forms a parallellogram, then MN and M'N' will be the oppposite sides. So, we can prove that MN=M'N'.

To prove MNN'M' is a parallelogram, we have to first prove that two pairs of opposite sides are parallel,

Slope of MN= Slope of M'N'.

Slope of MM'=NN'.

$\begin{gathered} \text{Slope of MN=}\frac{y2-y1}{x2-x1} \\ =\frac{1-(-1)}{3-(-2)} \\ =\frac{2}{5} \\ \text{Slope of M'N'=}\frac{y4-y3}{x4-x3} \\ =\frac{4-2}{5-0} \\ =\frac{2}{5} \end{gathered}$

Hence, slope of MN=Slope of M'N' and therefore, MN parallel to M'N'

$\begin{gathered} \text{Slope of MM'=}\frac{y3-y1}{x3-x1} \\ =\frac{4-(-1)}{5-(-2)} \\ =\frac{3}{2} \\ \text{Slope of NN'=}\frac{y4-y2}{x4-x2} \\ =\frac{4-1}{5-3} \\ =\frac{3}{2} \end{gathered}$

Hence, slope of MM'=Slope of NN' nd therefore, MM' parallel to NN'.

Since both pairs of opposite sides of MNN'M' are parallel, MM'N'N is a parallelogram.

Since the opposite sides are of equal length in a parallelogram, it is proved that segments MN and M'N' have the same length.

7 0

1 year ago