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wlad13 [49]
3 years ago
9

3. William and his family eat at a fancy restaurant that automatically

Mathematics
1 answer:
stellarik [79]3 years ago
3 0

Answer:

Step-by-step explanation

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What is this I need help
Setler79 [48]

Answer:

B. No solution

Step-by-step explanation:

2y-7\left(y+8\right)=1-5y\\\\\mathrm{Expand}\:-7\left(y+8\right):\quad -7y-56\\2y-7y-56=1-5y\\\\\mathrm{Add\:similar\:elements:}\:2y-7y=-5y\\-5y-56=1-5y\\\\\mathrm{Add\:}56\mathrm{\:to\:both\:sides}\\-5y-56+56=1-5y+56\\\\Simplify\\-5y=-5y+57\\\\\mathrm{Add\:}5y\mathrm{\:to\:both\:sides}\\-5y+5y=-5y+57+5y\\\\Simplify\\0=57

4 0
3 years ago
Read 2 more answers
Find the function y1 of t which is the solution of 121y′′+110y′−24y=0 with initial conditions y1(0)=1,y′1(0)=0. y1= Note: y1 is
strojnjashka [21]

Answer:

Step-by-step explanation:

The original equation is 121y''+110y'-24y=0. We propose that the solution of this equations is of the form y = Ae^{rt}. Then, by replacing the derivatives we get the following

121r^2Ae^{rt}+110rAe^{rt}-24Ae^{rt}=0= Ae^{rt}(121r^2+110r-24)

Since we want a non trival solution, it must happen that A is different from zero. Also, the exponential function is always positive, then it must happen that

121r^2+110r-24=0

Recall that the roots of a polynomial of the form ax^2+bx+c are given by the formula

x = \frac{-b \pm \sqrt[]{b^2-4ac}}{2a}

In our case a = 121, b = 110 and c = -24. Using the formula we get the solutions

r_1 = -\frac{12}{11}

r_2 = \frac{2}{11}

So, in this case, the general solution is y = c_1 e^{\frac{-12t}{11}} + c_2 e^{\frac{2t}{11}}

a) In the first case, we are given that y(0) = 1 and y'(0) = 0. By differentiating the general solution and replacing t by 0 we get the equations

c_1 + c_2 = 1

c_1\frac{-12}{11} + c_2\frac{2}{11} = 0(or equivalently c_2 = 6c_1

By replacing the second equation in the first one, we get 7c_1 = 1 which implies that c_1 = \frac{1}{7}, c_2 = \frac{6}{7}.

So y_1 = \frac{1}{7}e^{\frac{-12t}{11}} + \frac{6}{7}e^{\frac{2t}{11}}

b) By using y(0) =0 and y'(0)=1 we get the equations

c_1+c_2 =0

c_1\frac{-12}{11} + c_2\frac{2}{11} = 1(or equivalently -12c_1+2c_2 = 11

By solving this system, the solution is c_1 = \frac{-11}{14}, c_2 = \frac{11}{14}

Then y_2 = \frac{-11}{14}e^{\frac{-12t}{11}} + \frac{11}{14} e^{\frac{2t}{11}}

c)

The Wronskian of the solutions is calculated as the determinant of the following matrix

\left| \begin{matrix}y_1 & y_2 \\ y_1' & y_2'\end{matrix}\right|= W(t) = y_1\cdot y_2'-y_1'y_2

By plugging the values of y_1 and

We can check this by using Abel's theorem. Given a second degree differential equation of the form y''+p(x)y'+q(x)y the wronskian is given by

e^{\int -p(x) dx}

In this case, by dividing the equation by 121 we get that p(x) = 10/11. So the wronskian is

e^{\int -\frac{10}{11} dx} = e^{\frac{-10x}{11}}

Note that this function is always positive, and thus, never zero. So y_1, y_2 is a fundamental set of solutions.

8 0
3 years ago
Write the following situation in slope intercept form - y=mx+b
cestrela7 [59]
I think the answer is C
3 0
3 years ago
The population standard deviation for the temperature of beers found in Scooter's Tavern is 0.26 degrees. If we want to be 90% c
siniylev [52]

Answer:

19 beers must be sampled.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.9}{2} = 0.05

Now, we have to find z in the Z-table as such z has a p-value of 1 - \alpha.

That is z with a pvalue of 1 - 0.05 = 0.95, so Z = 1.645.

Now, find the margin of error M as such

M = z\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

The population standard deviation for the temperature of beers found in Scooter's Tavern is 0.26 degrees.

This means that \sigma = 0.26

If we want to be 90% confident that the sample mean beer temperature is within 0.1 degrees of the true mean temperature, how many beers must we sample?

This is n for which M = 0.1. So

M = z\frac{\sigma}{\sqrt{n}}

0.1 = 1.645\frac{0.26}{\sqrt{n}}

0.1\sqrt{n} = 1.645*0.26

\sqrt{n} = \frac{1.645*0.26}{0.1}

(\sqrt{n})^2 = (\frac{1.645*0.26}{0.1})^2

n = 18.3

Rounding up:

19 beers must be sampled.

7 0
3 years ago
6) find HJ<br> 8)find IK
Anastasy [175]

Answer:

HJ = 17

IK = 30

Step-by-step explanation:

to find HI :

GH : 2

HI : ?

IJ : 12

GI : 7

HI = GI - GH

HI = 7- 2

HI = 5

HI + IJ = HJ

5 + 12 = HJ

17 = HJ

To find IK

IJ = ?

JK = 12

KL = ?

IL = 49

JL = 31

To find IK we need to find KL and IJ

KL = JL - JK

KL = 31 - 12

KL = 19

IJ = IL - (JK + KL)

IJ = 49 - 31

IJ = 18

IK = IJ + JK

IK = 18 + 12

IK = 30

4 0
3 years ago
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