Answer:
the first sentance is wrong, the second one is right, the third one is right and the last one is wrong
Step-by-step explanation:
The solid line indicates that the line itself is included in the solutions. That the shaded area is to the left, or under, the line means that y≤the line.
To find the equation of the line you first find the slope or m using any two points.
m=(y2-y1)/(x2-x1) in this case you are given (2,-5) and (-2, 3) so
m=(3--5)/(-2-2)
m=8/-4
m=-2
So far for y≤mx+b we have:
y=-2x+b using either point we can solve for b, I'll use (2,-5)
-5=-2(2)+b
-5=-4+b
-1=b
So the line is:
y=-2x-1 and since y≤ the line:
y≤-2x-1
Answer:
Ф = 0 and Ф = π
Step-by-step explanation:
* Lets explain how to solve the problem
∵ sin Ф + 1 = cos²Ф, where 0 ≤ Ф < 2π
- To solve we must to replace cos²Ф by 1 - sin²Ф
∵ sin²Ф + cos²Ф = 1
- By subtracting sin²Ф from both sides
∴ cos²Ф = 1 - sin²Ф
- Lets replace cos²Ф in the equation above
∴ sin Ф + 1 = 1 - sin²Ф
- Subtract 1 from both sides
∴ sin Ф = - sin²Ф
- Add sin²Ф for both sides
∴ sin²Ф + sin Ф = 0
- Take sin Ф as a common factor from both sides
∴ sin Ф(sin Ф + 1) = 0
- Equate each factor by 0
∵ sin Ф = 0
∴ Ф = 0 OR Ф = 2π
∵ sin Ф + 1 = 0
- Subtract 1 from both sides
∴ sin Ф = -1
∴ Ф = π
∵ 0 ≤ Ф < 2π
∵ Ф < 2π
∴ We will refused the answer Ф = 2π
∴ Ф = 0 and Ф = π
Answer:
Step-by-step explanation:
We are given that:
Where <em>A</em> is in QI.
And we want to find sec(A).
Recall that cosecant is the ratio of the hypotenuse to the opposite side. So, find the adjacent side using the Pythagorean Theorem:
So, with respect to <em>A</em>, our adjacent side is 63, our opposite side is 16, and our hypotenuse is 65.
Since <em>A</em> is in QI, all of our trigonometric ratios will be positive.
Secant is the ratio of the hypotenuse to the adjacent. Hence:
The two sides marked 7 are congruent.
Sides AC and AD are congruent.
Sides BC and ED are congruent.
By SSS, the triangles are congruent.
Also, angles BAC and EAD are congruent, so by SAS, the triangles are congruent.
Answer: A. yes, by either SSS or SAS
