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aleksley [76]
3 years ago
15

Help plz:)))I’ll mark u Brainliest

Mathematics
1 answer:
notka56 [123]3 years ago
6 0

Answer:

21/35

Step-by-step explanation:

Given :

  • A right angled triangle with sides 28 , 35 ,21 .

And we need to find the value of cos A. We know that cosine is the ratio of base and Hypotenuse. So that ,

:\implies cos A = b/h

:\implies cosA = 21/35

  • :\implies <u>Hence </u><u>the</u><u> </u><u>required</u><u> </u><u>Answer</u><u> </u><u>is </u><u>2</u><u>1</u><u>/</u><u>35</u><u>.</u>
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Find the Prime Factorization of -165
Ghella [55]

Answer:

(-1)(11)(3)(5)

Step-by-step explanation:

First off:  -165 separates into the factors (-1) and (165).  Next, we divide 165 by 15, obtaining 15(11).

So far, we have (-1)(11)(15).

15 is still factorable.  We get:

(-1)(11)(3)(5), which is the desired prime factorization of -165.

6 0
3 years ago
200 people are asked about three brands of beverages Coffee, Tea and Chocolate. 36 like
Scorpion4ik [409]

Answer:

32

Step-by-step explanation:

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1 year ago
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a machine can produce 6 yards of fabric in 2 minutes how much fabric can the machine produce in 2 hours?
Mariulka [41]

Answer:

360 yards in 2 hours

Step-by-step explanation:

6 yards in 2 minutes = 3 yards in 1 minute

2 hours = 120 minutes

3*120

360 yards

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3 years ago
What eigen value for this matix <br> (1 -2)<br> (-2 0)
natali 33 [55]

You find the eigenvalues of a matrix A by following these steps:

  1. Compute the matrix A' = A-\lambda I, where I is the identity matrix (1s on the diagonal, 0s elsewhere)
  2. Compute the determinant of A'
  3. Set the determinant of A' equal to zero and solve for lambda.

So, in this case, we have

A = \left[\begin{array}{cc}1&-2\\-2&0\end{array}\right] \implies A'=\left[\begin{array}{cc}1&-2\\-2&0\end{array}\right]-\left[\begin{array}{cc}\lambda&0\\0&\lambda\end{array}\right]=\left[\begin{array}{cc}1-\lambda&-2\\-2&-\lambda\end{array}\right]

The determinant of this matrix is

\left|\begin{array}{cc}1-\lambda&-2\\-2&-\lambda\end{array}\right| = -\lambda(1-\lambda)-(-2)(-2) = \lambda^2-\lambda-4

Finally, we have

\lambda^2-\lambda-4=0 \iff \lambda = \dfrac{1\pm\sqrt{17}}{2}

So, the two eigenvalues are

\lambda_1 = \dfrac{1+\sqrt{17}}{2},\quad \lambda_2 = \dfrac{1-\sqrt{17}}{2}

5 0
2 years ago
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Set up a proportion and solve each problem. Round each answer to the nearest tenths. 5) What is 35% of 74? 6) 78 is what percent
prisoha [69]

Answer:

5)  35 / 100 = X / 74      X = 2590 / 100 = 25.9

or .35 * 74 = 25.9

6) 78 / 95 = X * 100

X = 7800 / 95 = 82.1 %

or X = 78/95 * 100 = 82.1 %

7)  60/100 * X = 28

X = 2800 / 60 = 46.7

Or .6 * X = 28

X = .28 / .6 = 46.7

8 0
2 years ago
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