Hello,
r=5(1+cos t)
r'=5(-sin t)
r²+r'²= 25[(1+cos t)²+(-sin t)²]=50(1-cos t)=50 sin² (t/2)
Between 0 and π, sin x>0 ==>|sin x|=sin x
![l= 2*5* \int\limits^{\pi}_0{sin( \frac{t}{2} )} \, dt= 5[-cos (t/2)]_0^{\pi}\\\\ =5(0+1)=5](https://tex.z-dn.net/?f=l%3D%202%2A5%2A%20%5Cint%5Climits%5E%7B%5Cpi%7D_0%7Bsin%28%20%5Cfrac%7Bt%7D%7B2%7D%20%29%7D%20%5C%2C%20dt%3D%205%5B-cos%20%28t%2F2%29%5D_0%5E%7B%5Cpi%7D%5C%5C%5C%5C%0A%3D5%280%2B1%29%3D5)
Here is the method but i may have make some mistakes.
4.5{4_x}+36=202-2.5{3+28}
you first multiply 4.5 and the numbers in the bracket.
4.5*4=18
4.5*x=4.5x
you will obtain 18-4.5x=202_2.5{3+28}
2.5*3=7.5 2.5*28=70
18_4.5x=202_7.5_70
18_4.5x=124.5_18
-4.5x=106.5
x=23.67
Answer:13 meters per second
Step-by-step explanation:
It is 2 and 3/5 your welcome :)
Answer:
Solve for x: -5/6x= -10/3 x=?
x = 1/4
Step-by-step explanation:
from the equation ,Solve for x: -5/6x= -10/3 , to solve for x we will first cross multiply
we have; -15= -60x
divide both sides by -60
-15/-60 = -60x/-60
x = 15/60 ( the minus will cancel out)
x = 1/4
check for your answer by putting 1/4 where you see x
i.e -5/6(1/4) = -10/3
-5 × 2/3 = -10/3
-10/3 = -10/3......... proved!!
