hello :<span>
<span>an equation of the circle Center at the
A(a,b) and ridus : r is :
(x-a)² +(y-b)² = r²
in this exercice : a = -7 and b = -1 (Center at: A(-7,-1) )
r = AP.... P(8,7)
r² = (AP)²
r² = (8+7)² +(7+1)² =225+64=289 ...... so : r = 17
an equation of the circle that satisfies the stated conditions.
Center at </span></span>A(-7,-1), passing through P(8, 7) is :
(x+7)² +(y+1)² = 289
The point (-15,y ) <span>lies on this circle : (-15+7)² +(y+1)² = 289....(subsct : x= -15)
(y+1)² = 225
(y+1)² = 15²
y+1 = 15 or y+1 = -15
y = 14 or y = -16
you have two points : (-15,14) , (-15, -16)</span>
Answer:
x=-2
Step-by-step explanation:
Answer:23%, 0.634, 3/4, 8/10
Answer:
n = 32 - 14 (= 18)
Step-by-step explanation:
You haven't given the answer options, however I assume it will be written in this form. I.e. the number of cupcakes still needed is just the total number of students (32) minus the number that Jenna bought (14).
so n = 32 -14 (=18)
Answer:
- 2x - 31
Step-by-step explanation:
Given
- 3(4x + 5) - 2(- 5x + 8)
Multiply the terms in the first parenthesis by - 3 and the terms in the second parenthesis by - 2
= - 12x - 15 + 10x - 16 ← collect like terms
= (- 12x + 10x) + (- 15 - 16)
= - 2x - 31