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3 years ago

Which point on the number line is closest to the product of the numbers graphed at points R and T? Explain your answer.

Mathematics

1 answer:

victus00 [196]3 years ago

5 0

Answer Point R = 7/10

and Point T = 9/10

7/10 · 9/10 = 63

63/100

6 /10 = point Q.

Step-by-step explanation:

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X+3y=28 when x =28 find the value for y plz help

Lisa [10]

Answer:

y = 0

Step-by-step explanation:

Plug in 28 for x. Solve for the equation:

x + 3y = 28

(28) + 3y = 28

Isolate the variable, y. Note the equal sign, what you do to one side, you do to the other. Do the opposite of PEMDAS. First, subtract 28 from both sides:

28 (-28) + 3y = 28 (-28)

3y = 0

Isolate the variable, y. Divide 3 from both sides:

(3y)/3 = (0)/3

y = 0

y = 0 is your answer.

4 0

3 years ago

If i make 10 fruit baskets and want to sell them for $35 each 10=35x what's my answer

ivolga24 [154]

You made a teeny mistake! Instead of 10=35x, it should be (35)(10)=x; so in this case, you would make $350 from 10 fruit baskets.

8 0

3 years ago

(10 1/4 - 5 5/8) - 1 3/8

Allisa [31]

3 1/4

should be it!

Hope that helps!

5 0

3 years ago

Use the given information to find the exact value of the trigonometric function

eimsori [14]

$\begin{gathered} \csc \theta=-\frac{6}{5} \\ \tan \theta>0 \\ \cos \frac{\theta}{2}=\text{?} \end{gathered}$

Half Angle Formula

$\cos \frac{\theta}{2}=\pm\sqrt[\square]{\frac{1+\cos\theta}{2}}$ $\tan \theta>0\text{ and csc}\theta\text{ is negative in the third quadrant}$ $\begin{gathered} \csc \theta=-\frac{6}{5}=\frac{r}{y} \\ x^2+y^2=r^2 \\ x=\pm\sqrt[\square]{r^2-y^2} \\ x=\pm\sqrt[\square]{6^2-(-5)^2} \\ x=\pm\sqrt[\square]{36-25} \\ x=\pm\sqrt[\square]{11} \\ \text{x is negative since the angle is on the 3rd quadrant} \end{gathered}$ $\begin{gathered} \cos \theta=\frac{x}{r}=\frac{-\sqrt[\square]{11}}{6} \\ \cos \frac{\theta}{2}=\pm\sqrt[\square]{\frac{1+\cos\theta}{2}} \\ \cos \frac{\theta}{2}is\text{ also negative in the 3rd quadrant} \\ \cos \frac{\theta}{2}=-\sqrt[\square]{\frac{1+\frac{-\sqrt[\square]{11}}{6}}{2}} \\ \cos \frac{\theta}{2}=-\sqrt[\square]{\frac{\frac{6-\sqrt[\square]{11}}{6}}{2}} \\ \cos \frac{\theta}{2}=-\sqrt[\square]{\frac{6-\sqrt[\square]{11}}{12}} \\ \\ \end{gathered}$

Answer:

$\cos \frac{\theta}{2}=-\sqrt[\square]{\frac{6-\sqrt[\square]{11}}{12}}$

Checking:

$\begin{gathered} \frac{\theta}{2}=\cos ^{-1}(-\sqrt[\square]{\frac{6-\sqrt[\square]{11}}{12}}) \\ \frac{\theta}{2}=118.22^{\circ} \\ \theta=236.44^{\circ}\text{ (3rd quadrant)} \end{gathered}$

Also,

$\csc \theta=\frac{1}{\sin\theta}=\frac{1}{\sin (236.44)}=-\frac{6}{5}\text{ QED}$

The answer is none of the choices

7 0

1 year ago

Payton has 2 pizzas. each pizza is cut into 10 equal slices. she and her friends eat 14 slices. what part of the pizzas did they

kakasveta [241]

14 / 20 total slices = 7 / 10, which is 0.7 if you're looking for a decimal.
That's 70% of the pizza, which I would eat by myself.

3 0

3 years ago

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