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Vaselesa [24]
3 years ago
12

A clinical trial was conducted to test the effectiveness of a drug for treating insomnia in older subjects. Before​ treatment, 2

2 subjects had a mean wake time of 105.0 min. After​ treatment, the 22 subjects had a mean wake time of 95.7 min and a standard deviation of 22.2 min. Assume that the 22 sample values appear to be from a normally distributed population and construct a 99​% confidence interval estimate of the mean wake time for a population with drug treatments. What does the result suggest about the mean wake time of 105.0 min before the​ treatment? Does the drug appear to be​ effective?
Mathematics
1 answer:
ahrayia [7]3 years ago
7 0

Answer:

Step-by-step explanation:

We want to determine a 99% confidence interval estimate of the mean wake time for a population with drug treatments.

Number of sample, n = 22

Mean, u = 95.7 min

Standard deviation, s = 22.2 min

For a confidence level of 90%, the corresponding z value is 2.58.

We will apply the formula

Confidence interval

= mean ± z × standard deviation/√n

It becomes

95.7 ± 2.58 × 22.2/√22

= 95.7 ± 12.21

The lower end of the confidence interval is 95.7 - 12.21 = 83.49 min

The upper end of the confidence interval is 95.7 + 12.21 = 107.91 min

The result suggests that there is no significant difference between the mean wake time before and after treatment. Therefore, the drug does not appear to be effective.

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Solution for 47 is what percent of 61:

47:61*100 =

(47*100):61 =

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Now we have: 47 is what percent of 61 = 77.05

Question: 47 is what percent of 61?

Percentage solution with steps:

Step 1: We make the assumption that 61 is 100% since it is our output value.

Step 2: We next represent the value we seek with $x$x​.

Step 3: From step 1, it follows that $100\%=61$100%=61​.

Step 4: In the same vein, $x\%=47$x%=47​.

Step 5: This gives us a pair of simple equations:

$100\%=61(1)$100%=61(1)​.

$x\%=47(2)$x%=47(2)​.

Step 6: By simply dividing equation 1 by equation 2 and taking note of the fact that both the LHS
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$\frac{100\%}{x\%}=\frac{61}{47}$
100%
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47​​

Step 7: Taking the inverse (or reciprocal) of both sides yields

$\frac{x\%}{100\%}=\frac{47}{61}$
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$\Rightarrow x=77.05\%$⇒x=77.05%​

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