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konstantin123 [22]
2 years ago
12

If ZP and ZQ are complementary angles,

Mathematics
1 answer:
nikdorinn [45]2 years ago
8 0
The answer for this question is A because x is equivalent to 4
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Find the length of the hypotenuse of a 45°-45°-90° triangle with a leg<br> length of 8 centimeters.
MArishka [77]

Answer:

8\sqrt{2 =\sqrt{128 = 11.31

Step-by-step explanation:

3 0
3 years ago
Please answer correctly !!!!!! Will mark brainliest !!!!!!!!!!!!!
romanna [79]

Answer:

x = - 9, x = 10

Step-by-step explanation:

Given

x² - x - 90 = 0

Consider the factors of the constant term (- 90) which sum to give the coefficient of the x- term (- 1)

The factors are - 10 and + 9, since

- 10 × 9 = - 90 and - 10 + 9 = - 1 , thus

(x - 10)(x + 9) = 0 ← in factored form

Equate each factor to zero and solve for x

x - 10 = 0 ⇒ x = 10

x + 9 = 0 ⇒ x = - 9

lesser x = - 9

greater x = 10

5 0
2 years ago
Please help, the questions just have to be simplified
dimaraw [331]
6c^2d^{-3}\ \times\ 3c^3d^{-4}=6\cdot3\cdot c^{2+3}d^{-3+(-4)}=18c^5d^{-7}=\frac{18c^5}{d^7}


\frac{-16p^6q^5}{20q^7}=-\frac{16}{20}p^6q^{5-7}=-\frac{4}{5}p^6q^{-2}=-\frac{4p^5}{5q^2}
8 0
3 years ago
Read 2 more answers
You want to mix a 5% blue dye with a 20% blue dye to make a 12% blue dye. The function y =100(0.05)+x(0.2)/100+x gives the conce
Natalija [7]
Y = 12% = 0.12

y = 100(0.05) + x(0.2) / 100 + x
0.12 = 5 + 0.2x / 100 + x
0.12( 100 + x ) = 5 + 0.2x
12 + 0.12x = 5 + 0.2x
7 = 0.08x
x = 87.5

hope this help
6 0
3 years ago
Read 2 more answers
if you were to solve the following system by substitution, what would be the best variable to solve for and from what equation?
Romashka-Z-Leto [24]

Answer:

see below

Step-by-step explanation:

2x+8y=12 3x-8y=11

If we have to solve by substitution, Take the first equation and divide by 2

2x/2 + 8y/2 =12/2

x+4y = 6

Then subtract 4y from each side

x = 6 -4y

Then substitute this into the second equation

This is best solved by elimination

2x+8y=12

3x-8y=11

----------------

5x = 36

x = 36/5

6 0
2 years ago
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