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cestrela7 [59]
3 years ago
5

Hat is equivalent to but different from 7/13

Mathematics
1 answer:
Rainbow [258]3 years ago
8 0

Answer and Step-by-step explanation:

The answer is \frac{14}{26}.

This fraction is a multiple of \frac{7}{13}.

<u><em>#teamtrees #PAW (Plant And Water)</em></u>

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What is the equation in slope-intercept form of the linear function represented by the table? x y –6 –18 –1 –8 4 2 9 12 y = nega
svetoff [14.1K]

Answer:

y = 2 x minus 6

Step-by-step explanation:

(-6,-18) and (-1,-8)

Slope: (-8 - -18)/(-1 - -6)

10/5

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y = 2x + c

-8 = 2(-1) + c

-8 = -2 + c

c = -6

y = 2x - 6

y = 2x - 4

4 0
3 years ago
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What is the coefficient of 12x -50=460
kogti [31]

Answer:

12

Step-by-step explanation:


5 0
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convert the following logarithmic equation to the equivalent exponential equation. Use the caret (^) to enter exponents. y=ln x
GarryVolchara [31]
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5 0
4 years ago
Which of the following is not equal to sin⁡(-230°)?
xenn [34]

From trigonometry we know that:

if sin(\theta)=sin(\alpha)

then, \theta=n\pi+(-1)^n\alpha (where n is an integer)

This can be rewritten in degrees as:

\theta=n(180^{\circ})+(-1)^n\alpha.............(Equation 1)

Now, in our case, \alpha=-230^{\circ}

Therefore, (Equation 1) can be written as:

\theta=n(180^{\circ})+(-1)^n(-230^{\circ})..........(Equation 2)

Now, to find the correct options all that we have to do is replace n by relevant integers and find the values of \theta that match.

For n=2, (Equation 2) gives us: \theta=2\times 180^{\circ}+(-1)^2(-230^{\circ})=360^{\circ}-230^{\circ}=130^{\circ}.

Thus, sin(230^{\circ})=sin(130^{\circ})

Now, we know that: -sin(-50^{\circ})=sin(50^{\circ})

Let n=-1, then:

\theta=(-1)\times 180^{\circ}+(-1)^{-1}(-230^{\circ})=-180^{\circ}+230^{\circ}=50^{\circ}

Thus, sin(-230^{\circ})=-sin(-50^{\circ})

Likewise, sin(-230^{\circ})=sin(50^{\circ})

Only the last option sin(-50^{\circ}) will never match sin(-230^{\circ}) because no integral value of n will ever give \theta=-50^{\circ}

Thus the last option is the correct option.

3 0
3 years ago
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Please help!!<br> Question is in the picture!!
Debora [2.8K]

\frac{17}{60} and \frac{1}{4} are the experimental probabilities from the table.

Solution:

Total number of times spun the spinner = 60

Number of times getting 1 = 12

Number of times getting 2 = 17

Number of times getting 3 = 15

Number of times getting 4 = 16

<u>Experimental probabilities from the table:</u>

Probability of getting 1 = \frac{12}{60}=\frac{1}{5}

Probability of getting 2 = \frac{17}{60}

Probability of getting 3 = \frac{15}{60}=\frac{1}{4}

Probability of getting 4 = \frac{16}{60}=\frac{4}{15}

<u>To determine which are the experimental probabilities from the table:</u>

Option A: 15

This is not obtained above. So, it is not the experimental probability.

Option B: \frac{17}{60}

This is obtained in the probability of getting 2.

So, it is the experimental probability.

Option C: \frac{1}{4}

This is obtained in the probability of getting 3.

So, it is the experimental probability.

Option D: \frac{7}{15}

This is not obtained above. So, it is not the experimental probability.

Option E: \frac{12}{43}

This is not obtained above. So, it is not the experimental probability.

Hence \frac{17}{60} and \frac{1}{4} are the experimental probabilities from the table.

5 0
3 years ago
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