1. 2x^2-x-15=0
A = 2
B = -1
C = -15
2. 10^2-2x=0
A = 10
B = -2
C = 0
3. x^2–3x-40=0
A = 1
B = -3
C = -40
4. x^2+3x-2=0
A = 1
B = 3
C = -2
5. 4x^2-17x+8=0
A = 4
B = -17
C = 8
Remember the equations should look like Ax^2+Bx+C=0 (in this order!!)
<span>If m = 7x + 7, m = 4y, and m = 112
since m = 112
112 = 7x + 7
112 - 7 = 7x
105= 7x
x = 15
112 = 4y
y = 28</span>
Answer:
No extraneous solution
Step-by-step explanation:
We have the logarithmic equation given by,
![\log_{2}[\log_{2}(\sqrt{4x})]=1](https://tex.z-dn.net/?f=%5Clog_%7B2%7D%5B%5Clog_%7B2%7D%28%5Csqrt%7B4x%7D%29%5D%3D1)
i.e. 
i.e. 
i.e. 
i.e. 
i.e. 
i.e. 
So, the solution of the given equation is x=4.
Now, as we domain of square root function is x > 0 and also, the domain of logarithmic function is
.
Therefore, the domain of the given function is x > 0.
We know that the extraneous solution is the solution which does not belong to the domain.
But as x=4 belongs to the domain x > 0.
Thus, x = 4 is not an extraneous solution.
Hence, this equation does not have any extraneous solution.
Find percent -> 2nd month.
4264*.25==1066 phone calls+=4264
==5330 for 2nd month.
for 2nd -> 3rd
6396==5330*x, solve algebraically to get .20 == 20% increase from 2nd month to 3rd month.
She drinks 4.27 grams on calcium in 14 days at one glass of milk containing 14 mg per day