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Firdavs [7]
2 years ago
9

I need help please i would be grateful

Mathematics
1 answer:
vitfil [10]2 years ago
3 0
N+9

The other factor is n-6

Once multiple together, you will get the same equation again
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2/15 net 45 translates as​ ________. A. 45 percent of account due in 15​ days, payment prior to day 15 receives a 2 percent disc
Elena-2011 [213]

Answer:

C. 2 percent cash discount if paid prior to 15 days, if customer does not take a cash discount, the balance is due in 45 days.

Step-by-step explanation:

2/15 net 45 translates as 2 percent cash discount if paid prior to 15 days, if customer does not take a cash discount, the balance is due in 45 days.

4 0
3 years ago
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Please answer question now
nata0808 [166]

Answer:

469.42 ft²

Step-by-step explanation:

  • Law of sines;

         w/sin27 = 38/sin40

                   w = sin27*38/sin40

                    w = 26.84 ft

  • Angle x;

            ∡X = 180 - 27- 40 = 113º

  • Area;

              A = 0.5*(26.84)*(38)*sin(113)

            A = 469.42 ft²

8 0
2 years ago
The probability that an event will occur is fraction 2 over 3 . Which of these best describes the likehood of the event occurrin
ELEN [110]
Likely best describes the likelihood of the probability 2/3.  It is not completely certain, nor is it unlikely, and it definitely cannot be impossible.
4 0
3 years ago
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The manager of a music store has kept records of
Marysya12 [62]

Answer:

(a) P(x\le 3) = 0.75

(b) P(x\le 3) = 0.75

<em>(b) is the same as (a)</em>

(c) P(x \ge 5) = 0.10

(d) P(x = 1\ or\ 2) = 0.55

(e) P(x > 2) = 0.45

Step-by-step explanation:

Given

\begin{array}{ccccccc}{CDs} & {1} & {2} & {3} & {4} & {5} & {6\ or\ more}\ \\ {Prob} & {0.30} & {0.25} & {0.20} & {0.15} & {0.05} & {0.05}\ \ \end{array}

Solving (a): Probability of 3 or fewer CDs

Here, we consider:

\begin{array}{cccc}{CDs} & {1} & {2} & {3} \ \\ {Prob} & {0.30} & {0.25} & {0.20} \ \ \end{array}

This probability is calculated as:

P(x\le 3) = P(1) + P(2) + P(3)

This gives:

P(x\le 3) = 0.30 + 0.25 + 0.20

P(x\le 3) = 0.75

Solving (b): Probability of at most 3 CDs

Here, we consider:

\begin{array}{cccc}{CDs} & {1} & {2} & {3} \ \\ {Prob} & {0.30} & {0.25} & {0.20} \ \ \end{array}

This probability is calculated as:

P(x\le 3) = P(1) + P(2) + P(3)

This gives:

P(x\le 3) = 0.30 + 0.25 + 0.20

P(x\le 3) = 0.75

<em>(b) is the same as (a)</em>

<em />

Solving (c): Probability of 5 or more CDs

Here, we consider:

\begin{array}{ccc}{CDs} & {5} & {6\ or\ more}\ \\ {Prob} & {0.05} & {0.05}\ \ \end{array}

This probability is calculated as:

P(x \ge 5) = P(5) + P(6\ or\ more)

This gives:

P(x\ge 5) = 0.05 + 0.05

P(x \ge 5) = 0.10

Solving (d): Probability of 1 or 2 CDs

Here, we consider:

\begin{array}{ccc}{CDs} & {1} & {2} \ \\ {Prob} & {0.30} & {0.25} \ \ \end{array}

This probability is calculated as:

P(x = 1\ or\ 2) = P(1) + P(2)

This gives:

P(x = 1\ or\ 2) = 0.30 + 0.25

P(x = 1\ or\ 2) = 0.55

Solving (e): Probability of more than 2 CDs

Here, we consider:

\begin{array}{ccccc}{CDs} & {3} & {4} & {5} & {6\ or\ more}\ \\ {Prob} & {0.20} & {0.15} & {0.05} & {0.05}\ \ \end{array}

This probability is calculated as:

P(x > 2) = P(3) + P(4) + P(5) + P(6\ or\ more)

This gives:

P(x > 2) = 0.20+ 0.15 + 0.05 + 0.05

P(x > 2) = 0.45

3 0
3 years ago
Can someone please help me I’m desperate it due tomorrowwww
zlopas [31]

Answer:

Step-by-step explanation:

First box: m=1/2

Second box: m=2

Third box: m=1

Fourth box: m=2

5 0
3 years ago
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