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Mashutka [201]
2 years ago
11

" \frac{5}{3} + \frac{4}{6} = " alt=" \frac{5}{3} + \frac{4}{6} = " align="absmiddle" class="latex-formula">
.................​
Mathematics
1 answer:
o-na [289]2 years ago
3 0

Answer:

\frac{7}{3} =2\frac{1}{3}

Step-by-step explanation:

For the problem:

\frac{5}{3} +\frac{4}{6} = ?

The Least Common Multiple (LCM) of 3 and 6 is 6. Multiply the numerator and denominator of each fraction by whatever value will result in the denominator of each fraction being equal to the LCM:

\frac{5}{3} +\frac{4}{6} =\frac{5*2}{3*2} +\frac{4}{6} =\frac{10}{6} +\frac{4}{6}

Now that the fractions have like denominators, add the numerators:

\frac{10}{6} +\frac{4}{6} =\frac{10+4}{6} =\frac{14}{6}

The Greatest Common Factor (GCF) of 14 and 6 is 2. The result can be simplified by dividing both the numerator and denominator by 2.

\frac{14}{6} =\frac{14/2}{6/2} =\frac{7}{3}

7 ÷ 3 = 2R1, therefore:

\frac{7}{3} =2\frac{1}{3}

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A triangular course for a canoe race is marked with buoys. The first leg is 3/10 mi, the second leg is 1/2 mi, and the third leg
balu736 [363]
<h2>The race is 1.2 miles long</h2>

Step-by-step explanation:

The first leg is 3/10 mi, the second leg is 1/2 mi, and the third leg is 2/5 mi.

\texttt{Length of first leg = }\frac{3}{10}miles\\\\\texttt{Length of second leg = }\frac{1}{2}miles\\\\\texttt{Length of third leg = }\frac{2}{5}miles

Now we need to find length of race

       \texttt{Total length = }\frac{3}{10}+\frac{1}{2}+\frac{2}{5}\\\\\texttt{Total length = }\frac{3}{10}+\frac{5}{10}+\frac{4}{10}\\\\\texttt{Total length = }\frac{3+5+4}{10}\\\\\texttt{Total length = }\frac{12}{10}\\\\\texttt{Total length = }1.2miles

The race is 1.2 miles long

7 0
3 years ago
−4x+7y+5= 0x−3y=−5​<br><br>How many solutions does the system have?
seraphim [82]
{-4x+7y+5=-5
{0x-3y=-5 Solve the equation.

{-4x+7y+5=-5
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x=65/12 You should get this answer.

Therefore: (x,y) = (65/12,5/3)
6 0
3 years ago
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